Consider that the three consecutive integers are:
least integer = n
middle integer = n + 1
greatest integer = n + 2
THe expression "three consecutive integers is 12 less than 4 times the middle integer" can be written as follow:
n + (n + 1) + (n + 2) = 4(n +1) - 12
In order to find the numbers, proceed as follow:
n + (n + 1) + (n + 2) = 4(n +1) - 12 cancel parenthesis
n + n + 1 + n + 2 = 4n + 4 - 12 simplify like terms
3n + 3 = 4n - 8 subtract 4n and 3 both sides
3n - 4n = - 8 - 3
-n = -11
n = 11
Hence, the three consecutive integers are:
n = 11
n + 1 = 12
n + 2 = 13
Answer:
$26532.98
Step-by-step explanation:
<u>Given:</u>
- Principal = $10000
- Profit rate = 5% PA compounded
- Time = 20 years
- Compounds = 20*1 = 20
<u>Sum is:</u>
- 10000*(1 + 5/100)²⁰ ≈ 26532.98
Answer:
y of what do you have at least a picture?
When we give x to second, then the third will be 2x and according to informations first one should be x-6. Then you have to sum all. It ll be equal to 4x-6.
78=4x-6
84=4x
21=x
So, first number is 15, second one is 21 and the last one is 42
