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Assoli18 [71]
3 years ago
6

The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways

can they choose three booths from a selection of nine? A 42 B 84 C 508 D 814
Mathematics
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B

Hope that helps!

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