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oee [108]
2 years ago
13

A playground has two sides that each measure 70 feet and two sides that each measure 50 foot. Select all the quadrilaterals that

describe the shape
of a playground with these dimensions.
The last one is trapezoid

Mathematics
1 answer:
Vlad1618 [11]2 years ago
3 0

Answer:

Rectangle

Step-by-step explanation:

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Which of the following expressions are equivalent?
shtirl [24]

Answer:

the second option

Step-by-step explanation:

5+(1+3)= (5+1) +3

hope this helps :)

5 0
2 years ago
at the middle school graduation dance, the dj played 12 slow dances, which was equal to the quotient of the number of fast dance
Zolol [24]
Quotient means that division was used so you do the opposite of division which is multiplication... so you do 12×2 and get 24 ...so 24 fast songs were played
7 0
3 years ago
Which statement is not true for the function notation of the volume of a cube, V(s) = s3?
Volgvan
<h3>Answer:</h3>

b. The side length of a cube is dependent on the volume.

<h3>Step-by-step explanation:</h3>

The function definition V(s) means the volume (V) is dependent upon the side length (s), <em>not the other way around</em>.

4 0
3 years ago
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
Some one please help. There is a pic down below
Ahat [919]
Could you send the picture so I could help please :)
3 0
3 years ago
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