1.6 : 4
1.6 is also equal to 8/5
therefore,
8/5 : 4
(8/5)/4
**get the reciprocal of the denominator (4) which is equal to 1/4**
(8/5)*(1/4)
(8/4)*(1/5)
2*(1/5)
2/5
two fifth is the answer
Answer:
p = 2 or p = -2 4/9
Step-by-step explanation:
We can substitute x=3/2 into the equation and solve for the values of p that make the result be zero.
p^2(3/2)^2 -12(3/2) +p +7 = 0
9/4p^2 -18 + p + 7 = 0 . . . . eliminate parentheses
9p^2 +4p -44 = 0 . . . . . . simplify and multiply by 4
(9p +22)(p -2) = 0 . . . . . factor
Values of p that make 3/2 be one of the zeros are ...
p = -22/9, p = 2
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<em>Additional comment</em>
The <em>zero product rule</em> tells you a product will be zero if and only if a factor is zero. Hence the solutions to the quadratic are values of p that make the factors zero.
9p +22 = 0 ⇒ 9p = -22 ⇒ p = -22/9
p -2 = 0 ⇒ p = 2
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For p=2, the solution 3/2 has multiplicity 2. For p=-22/9, the other zero is x=123/242.
Answer:
Step-by-step explanation:
hello :
15r² – 6r – 3 = -2r
15r² – 6r – 3 +2r =0
15r²-4r -3 =0
delta =b² -4ac a=15 b=-4 c=-3
delta =(-4)² - 4(15)(-3)=196 = 14²
r1 = (-b - √delta ) /2a = (4-14)/30 = -10/30 = -2/6 = -1/3
r2 = (-b + √delta ) /2a = (4+14)/30 = 18/30 = 3/5
Answer:
The pythagorean identity that is correct is option B:
B. tan^2(theta)+1=sec^2(theta)
Step-by-step explanation:
The pythagorean identities are:
1.) sin^2(theta) + cos^2(theta) = 1
2.) tan^2(theta) + 1 = sec^2(theta)
3.) 1 + cot^2(theta) = csc^2(theta)
Then the pythagorean identity that is correct is option B:
B. tan^2(theta)+1=sec^2(theta)
Prime factorization is simply making a number become simplified in the smallest term it can be in. For example 9 Can be broken down into 3 times 3. Your prime numbers are 2, 3, 5, 7, 11, 13, 17,19 because nothing times something will give you that number besides itself and 1
