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ohaa [14]
3 years ago
11

Divide the following polynomials (2x2+x+3)/ (x-2)

Mathematics
1 answer:
Elza [17]3 years ago
5 0

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of

0

.

2

x

-

3

2

x

2

-

3

x

+

5

Divide the highest order term in the dividend

2

x

2

by the highest order term in divisor

2

x

.

x

2

x

-

3

2

x

2

-

3

x

+

5

Multiply the new quotient term by the divisor.

x

2

x

-

3

2

x

2

-

3

x

+

5

+

2

x

2

-

3

x

The expression needs to be subtracted from the dividend, so change all the signs in

2

x

2

−

3

x

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

0

Pull the next term from the original dividend down into the current dividend.

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

0

+

5

The final answer is the quotient plus the remainder over the divisor.

x

+

5

2

x

−

3

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Evaluate: x = y² if x = 8 and y = 3<br>A. 2<br>B. 509<br>C. 25<br>D. -1<br><br>​
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
In general, the point
Zanzabum

Answer:

we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.

Therefore, the point (0, a) is on the graph of the function f(x) = abˣ

Hence, option (D) is correct.

Step-by-step explanation:

Given the function

f(x) = abˣ

Let us substitute all the points one by one

FOR (b, 0)

y = abˣ

putting x = b, y = 0

0 = abᵇ

FOR (a, b)

y = abˣ

putting x = a, y = b

b = abᵃ

FOR (0, 0)

y = abˣ

putting x = 0, y = 0

0 = ab⁰

0 = a         ∵b⁰ = 1

FOR (0, a)

y = abˣ

putting x = 0, y = a

a = ab⁰

a = a         ∵b⁰ = 1

TRUE

Thus, we conclude that when we put the ordered pair (0, a), both sides of the function equation becomes the same.

Therefore, the point (0, a) is on the graph of the function f(x) = abˣ

Hence, option (D) is correct.

8 0
3 years ago
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