Question

Divide the following polynomials (2x2+x+3)/ (x-2)

Answer 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of

0

.

2

x

-

3

2

x

2

-

3

x

+

5

Divide the highest order term in the dividend

2

x

2

by the highest order term in divisor

2

x

.

x

2

x

-

3

2

x

2

-

3

x

+

5

Multiply the new quotient term by the divisor.

x

2

x

-

3

2

x

2

-

3

x

+

5

+

2

x

2

-

3

x

The expression needs to be subtracted from the dividend, so change all the signs in

2

x

2

−

3

x

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

0

Pull the next term from the original dividend down into the current dividend.

x

2

x

-

3

2

x

2

-

3

x

+

5

-

2

x

2

+

3

x

0

+

5

The final answer is the quotient plus the remainder over the divisor.

x

+

5

2

x

−

3