Question

Write a program to accept 10 different whole number from the user and store them in a

Answer 1

Explanation:

Question is not well presented:

The search strings in the question are not well formatted.

First thing, I'll arrange the account number in order of 7;

Meaning that the length of each account number is 7

8149420 5333174 3080098 6755963 9526981 4449539 9387197 5104726 2931356 4282637 1750219 6086650 3164838 2419590 4578589 9718904 674994 12545408

Answer:

// This program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include <iostream>

using namespace std;

// Initialise Function

int ArrayList(int[], int, int);

// Main Method starts at

int main()

{

// The list of account is 18; so, we Initialise an integer Variable to hold this value

const int acctlist = 18;

// Initialise an array to hold the account numbers

int List[acctlist] = { 8149420 5333174 3080098 6755963 9526981 4449539 9387197 5104726 2931356 4282637 1750219 6086650 3164838 2419590 4578589 9718904 674994 12545408

};

// Declare account number and search result Variables of type integer

int accountnumber, Result;

// Prompt user for account number

cout << "Enter a valid account number: ";

cin >> accountnumber;

// Determine if valid or not

Result = ArrayList(List, acctlist, accountnumber);

if(Result == -1){

cout << "Account number " << AcctNum << " is invalid.\n";}

else{

cout << "Account number " << List[Result] << " is valid\n";

}

return 0;

}

// Function starts here

int ArrayList(int list[], int size, int value)

{

int index = 0,

pos = -1;

bool seen = false;

// Check if Account number is seen in list

while (!seen && index < size)

{

if (list[index] == value)

{

seen = true;

}

pos = index;

}

index++