Answer:
41.3 °C
Explanation:
From the question given above, the following data were obtained:
Mass (M) of water = 27.56 g
Heat (Q) loss = 2443 J
Final temperature (T2) = 62.5 °C
Initial temperature (T1) =?
NOTE: The specific heat capacity (C) of water is 4.18 J/g°C
Thus, we can obtain the initial temperature of the water by using the following formula:
Q = MC(T2 – T1)
2443 = 27.56 × 4.18 (62.5 – T1)
2443 = 115.2008 (62.5 – T1)
Divide both side by 115.2008
2443 / 115.2008 = (62.5 – T1)
21.20645 = 62.5 – T1
Collect like terms
21.20645 – 62.5 = – T1
– 41.3 = – T1
Divide both side by – 1
– 41.3 /– 1= – T1 / –1
41.3 = T1
T1 = 41.3 °C
Thus, the initial temperature of the water was 41.3 °C
Answer: The Answer is A.
Explanation:
The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.
Hope this Helps!
Answer:
Explanation: the scientific notation used to calculate a mole is 6.022 x 1023.
Answer:
f = 7.5 E14 s-1
Explanation:
energy emitted by photon:
- E = h.c / λ.......(1)
- E = h.f......(2) Planck-Einstein
∴ λ = (400nm)(m/1 E9 nm) = 4.00 E-7 m
∴ h ( Planck's constant) = 6.626070150 E-34 J.s
∴ c (velocity of light) = 3.00 E8 m/s
∴ f (frequency): photon/s
If (1) = (2):
⇒ f = c / λ = E / h
⇒ f = (3.0 E8 m/s) / ( 4.00 E-7 m) = 7.5 E14 s-1