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3 years ago

What is the area of triangle IHC?

Mathematics

1 answer:

madam [21]3 years ago

8 0

Answer:

$28 cm^2$

Step-by-step explanation:

The formula for finding the area of a triangle is:

$\frac{1}{2} bh$

The "b," is the base (7), and the "h," is the height (8):

$\frac{1}{2} (7)(8)$

$\frac{1}{2} (56)$

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What is the 99th digit of pie?

il63 [147K]

First 99 digits.

3.1415926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 342117067

8 0

1 year ago

Read 2 more answers

The Mississippi River flows at a rate of 16,790 cubic meters per second. Choose the best approximation of the flow rate of the M

tatiyna

Answer:

B, 2(10^4)

Step-by-step explanation:

2(10^3)= 2000

2(10^4)= 20000

2(10^4) Is closer to 16790 than 2(10^3)

8 0

4 years ago

I'd really appreciate it if you'd help! :)

sergij07 [2.7K]

The answer to your question is

h=2y+36

why?

because he was already 36 inches which mean he would be adding on the inches.

So he would grow 2 inches a year plus the 36 inches he already was.

Hope this helps

5 0

4 years ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

In a parking garage the number of suv's is 40% greater than the number of automobiles. there are 98 suv's. how many automobiles

chubhunter [2.5K]

A=automobile S=SUV
0.4A+A=98 (to change a percent to a decimal you move the decimal point two places to the right)
1.4A=98 (I combined like terms)
A=70 (divided each side by 1.4)

3 0

3 years ago