Answer:
11 yes
12 H2O( water molecules)
13 3H2O( water molecules)
Explanation:
Sry, my phone's a potato, so I didn't read it properly, so I'm not sure about the question 11.
11-yes, they stay together, but they release 3 molecules of OH an H.
12- here it talks about what will happen with OH and H: they will be H2O (water molecules).
13- and here we end it with the informations that we got: 3 fatty acids+ glycerol---> fat+ 3H2O( the 3 H and 3 OH)
Answer:
Water has strong hydrogen bonds between molecules. These bonds require a lot of energy before they will break. This leads to water having a higher boiling point than if there were only weaker dipole-dipole forces. Water also has a high specific heat.
Explanation:
Hope this helped it is what I could find!
Answer:
3 atoms of O
8.57g
Explanation:
The problem here is to find the mass of oxygen in the compound and the number of atoms of oxygen.
The formula of the compound is:
NaHCO₃;
Here we have:
1 atom of Na
1 atom of H
1 atom of C
3 atoms of O
So there are 3 atoms of O
To find the mass of oxygen , we use the molar mass of oxygen;
Molar mass of oxygen = 16g/mol
Mass of oxygen =
x 15 = 8.57g
Answer:
During cellular respiration, plants take in carbon dioxide from the air and break down stored glucose.
Explanation:
Before cellular respiration takes place in a plant, photosynthesis occurs and absorbs sunlight and carbon dioxide from the air. The process then produces oxygen and glucose, which are needed as the reactants for cellular respiration. Cellular respiration will break down the stored glucose to make energy to produce carbon dioxide and water. Then the cycle repeats itself.
Answer:
83.64%.
Explanation:
∵ The percent yield = (actual yield/theoretical yield)*100.
actual yield of CO₂ = 2300 g.
- We need to find the theoretical yield of CO₂:
For the reaction:
<em>CH₄ + 2O₂ → 2H₂O + CO₂,</em>
1.0 mol of CH₄ react with 2 mol of O₂ to produce 2 mol of H₂O and 1.0 mol of CO₂.
- Firstly, we need to calculate the no. of moles of 1000 g of CH₄ using the relation:
<em>no. of moles of CH₄ = mass/molar mass</em> = (1000 g)/(16.0 g/mol) = <em>62.5 mol.</em>
<u><em>Using cross-multiplication:</em></u>
1.0 mol of CH₄ produces → 1.0 mol of CO₂, from stichiometry.
∴ 62.5 mol of CH₄ produces → 62.5 mol of CO₂.
- We can calculate the theoretical yield of carbon dioxide gas using the relation:
∴ The theoretical yield of CO₂ gas = n*molar mass = (62.5 mol)(44.0 g/mol) = 2750 g.
<em>∵ The percent yield = (actual yield/theoretical yield)*100.</em>
actual yield = 2300 g, theoretical yield = 2750 g.
<em>∴ the percent yield</em> = (2300 g/2750 g)*100 = <em>83.64%.</em>