0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n = 
putting the values in the equation:
n = 
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.
Answer:
1 mole of dinitrogen combined with 3 moles of diiodine yields 2 moles of nitrogen triiodide
Explanation:
Answer:
21.5mL of a 0.100M HCl are required
Explanation:
The sodium phenoxide reacts with HCl to produce phenol and NaCl in a 1:1 reaction.
To solve this question we need to find the moles of sodium phenoxide. These moles = Moles of HCl required to reach equivalence point and, with the concentration, we can find the needed volume as follows:
<em>Mass NaC6H5O:</em>
1.000g * 25% = 0.250g NaC6H5O
<em>Moles NaC6H5O -116.09g/mol-</em>
0.250g NaC6H5O * (1mol/116.09g) = 2.154x10⁻³ moles = Moles of HCl required
<em>Volume 0.100M HCl:</em>
2.154x10⁻³ moles HCl * (1L/0.100mol) = 0.0215L =
<h3>21.5mL of a 0.100M HCl are required</h3>
Here are the solutions
1. Double replacement
2. Combustion
3. Single replacement
4. Synthesis
5. Decomposition.
Answer:
The answer is D.
Explanation:
Volume (V) = l x w x h
V = 4 x 5 x 1.2
V = 20 x 1.2
V = 24
Density = Mass/Volume or D = M/V
D = 85,000/24
D = 3541.66666666
