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zhenek [66]
2 years ago
11

In an experiment, a solution required 30. 05 g of nacl, 50. 0 g of , and 0. 4006 g of mgso4. Using the correct number of signifi

cant figures, what is the resulting mass?.
Chemistry
1 answer:
Radda [10]2 years ago
7 0

When the use of significant figures and rounding up is applied correctly the mass of the mixture will be 80.5 g.

In cases of addition or subtraction, only the last significant figure of every number is taken into account.

In 30.05, this is 5, in the hundredths. When we look at 50.0, the last significant figure is 0, and it is in the tenths. And in 0.4006, the last significant figure is 6, in the ten thousandths. Of these three, the 0 from 50.0 is in the leftmost position, which means that the last significant figure of the result needs to be in the same position (in the tenths).

Moving onto the actual algebraic operation:

30.05 g + 50.0 g + 0.4006 = 80.4506 g

As we established, the last significant figure should be in the tenths, and we will have to round up 4 to 5 (trailing numbers are greater than 0), which means that the resulting mass will be 80.5 g.

You can learn more about significant figures here:

brainly.com/question/14804345

#SPJ4

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Answer:

The total volume of the buffer is 75,0mL

Explanation:

A buffer is a mixture of a weak acid with its conjugate base or a weak base with its conjugate acid.

The buffer than Stu and Doc made is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Doc add 30.0 mL of 0.0635 M CH₃COOH while Stu add 45.0 mL of 0.0285 M NaCH₃COO (CH₃COO⁻)

Thus, the total volume of the buffer is:

30,0mL + 45,0mL =<em> 75,0 mL</em>

I hope it helps!

5 0
3 years ago
What should we do<br> with the CO2?
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Answer:

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6 0
3 years ago
For a reaction for which AH = +29.3 kJ/mol and AS = +106 J/mol•K, which of the following statements is true? A) The reaction is
umka2103 [35]

Answer: A) The reaction is spontaneous above 276 K.

Explanation:

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

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\Delta S = entropy change  = +106 J/molK

T = temperature in Kelvin

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

\Delta G=(+ve)-T(+ve)

\Delta G=(+ve)(-ve)

T\Delta S>\Delta H  for reaction to be spontaneous

T\times 106 J/molK>29300J/mol

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Thus the Reaction is spontaneous when temperature is above 276 K.

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Answer:

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Explanation:

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