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gizmo_the_mogwai [7]
3 years ago
10

Find the value of x​

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
X=27

11x=16.5(18)
11x=297
x=27
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What is the answer to 99.55 divided by 1.1 worked out???
anygoal [31]

Answer:

90.5

Step-by-step explanation:

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6 0
3 years ago
The standard golf ball has a mass of 45g.How many golf balls are there in a bag weighing 1.8 kg?
mars1129 [50]
Bag weight 1.8 kg
Golf ball weight: 45g

1 kg = 1000g
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total bag weight / golf ball weight = total balls in bag
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6 0
3 years ago
Read 2 more answers
A stack of playing cards contains 4 jacks, 5 queens, 3 kings, and 3 aces. two cards will be randomly selected from the stack. wh
Kipish [7]

Answer:

1/9.

Step-by-step explanation:

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The probability of a second queen being chosen is also 1/3

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7 0
3 years ago
write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 40 to 56
masha68 [24]

Answer:

  5/7

Step-by-step explanation:

A common factor of 8 can be canceled from numerator and denominator.

  40/56 = (5·8)/(7·8) = (5/7)·(8/8) = (5/7)·1 = 5/7

_____

Since you know your multiplication tables, you know that 40 and 56 are both multiples of 8.

__

If you don't know your multiplication tables, you can find the greatest common divisor (GCD) of the two numbers and divide each by that. The GCD can be found using Euclid's algorithm. For that, you divide the larger by the smaller and use the remainder as the new smaller number. The original smaller number is now the larger number. For these numbers, that looks like ...

  56 ÷ 40 = 1 r 16

  40 ÷ 16 = 2 r 8

  16 ÷ 8 = 2 r 0 . . . . . the zero remainder signals that the divisor (8) is the GCD

Now, your fraction is ...

  (40/8) / (56/8) = 5/7

3 0
3 years ago
Read 2 more answers
How do you solve this
AlladinOne [14]

Answer:

  • domain: all terms are defined for <em>all real numbers</em>
  • solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6

6 0
3 years ago
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