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strojnjashka [21]
3 years ago
15

Explain why f(x) =√2+x - √2/x, is not continuous at x = 0. Picture provided below.

Mathematics
2 answers:
lord [1]3 years ago
8 0

Answer:

Choice A is correct. function is not defined at x = 0.

Step-by-step explanation:

We have given function:

f(x) = (√2+x - √2)/x

We have to explain that f(x) is not continuous at x = 0.

The domain is the values of x for which the function is difined.

So, at x=0 function is not defined.

Because x is in the denominator of function so when we put x=0 the function has no value.

f(x) = (√2+x - √2)/x  is not continuous at x = 0.

Choice A is correct.

IrinaK [193]3 years ago
3 0

Answer: A

Step-by-step explanation:

If you put 0 in for x, then you would be dividing by 0. Dividing by 0 is always undefined.

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Ivan
The answer is:  [A]:  " 20a − 5b − 9 " .
______________________________________
Explanation:
_______________________________________________
  (12a <span>+ 7b) + (−6a − 9) + (14a − 12b) =
 
   12a </span><span>+ 7b  +  1(−6a − 9) + 1(14a − 12b) =
</span>    
   12a + 7b + (1*-6a) + (1*-9) + (1*14a) + (1* -12b) =
      
    12a + 7b − 6a − 9 + 14a − 12b =  ?

Combine the "like terms:

12a − 6a  + 14a = 20a ; 

7b − 12b =  - 5b ;

and then we have "-9" ;
_____________________________________________________
So, write as:   " 20a − 5b − 9 " ;  which is:  Answer choice:  [A].
______________________________________________________
8 0
3 years ago
Read 2 more answers
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