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almond37 [142]
2 years ago
7

Desperate Please Hurry Up

Mathematics
1 answer:
irina1246 [14]2 years ago
4 0

Answer:

25

Step-by-step explanation:

Using the rules of BIDMAS, you first work out the calculation inside the bracket. y-z equals 25-20 which equals 5. then, you work out out the fraction. x=10 so 10/2 equals 5. Then, multiply the value inside the bracket (5) by the outside value(5). This equals 25

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Which is greater 5 8/10 or 58/10
NARA [144]
This is a trick question. the answer is neither, they are both equivalent to one another :)
8 0
3 years ago
Gamal is buying ham and turkey to make sandwiches for a party. At most, he can spend $50, and he must buy more than 8 pounds of
IRINA_888 [86]
H +t = 8
$6h + $7t ≤$50

h+t = 8
h +t-t=8-t
h= 8-t

$6(8-t) + $7t ≤$50
48-6t +7t≤50
48-48+t≤50-48
t ≤ 2
h=6

$6(6) + $7(2) ≤$50
36 + 14 ≤ 50
50≤50

He can buy 6 pounds of ham and 2 pounds of turkey
3 0
3 years ago
Read 2 more answers
7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0​
morpeh [17]

Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

  • Answer :

x = -4 or x = 2 ✅

  • Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

  • If b² - 4ac > 0 , There are 2 real-number solutions

  • If b² - 4ac = 0 , There is 1 real-number solution.

  • If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a}

Here, we have :

  • a = 1
  • b = 2
  • c = -8

1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

x_1 =  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  \\ x_1 =  \frac{ - 2 -  \sqrt{36} }{2(1) }  \\  \\ x_1 =  \frac{ - 2 - 6}{2}   \\ \\ x_1 =  \frac{ - 8}{2}  \\  \\ \blue{\boxed{\red{x_1 = -4}}}

▪️ (2)

x_2 =  \frac{ - b  +   \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\ x_2 =  \frac{ - 2 +  \sqrt{36} }{2(1)}  \\  \\ x_2 =  \frac{ - 2 + 6}{2}  \\  \\ x_2 =  \frac{4}{2}  \\  \\ \red{\boxed{\blue{x_2 = 2}}}

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

brainly.com/question/27638369

6 0
2 years ago
Read 2 more answers
Evaluating Algebraic Expressions
koban [17]
D + t = total earnings
$3h + t = total earnings
$3h + $22 = total earnings

Fill in h as however many hours she is working.
Example: She worked for 8 hrs and got $22 in tips.
$3(8) + $22 = ?
$24 +$22 = $46
6 0
3 years ago
I am confused. what is 5r– 7 = 2r+ 14
Vlada [557]

Answer:

r=7

Step-by-step explanation:

5r-7=2r+14

add sevento both sides

5r=2r+21

Subtract 2r from both sides.

3r=21

divide both sides by 3

r=7

5 0
3 years ago
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