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docker41 [41]
3 years ago
12

Cynthia earns $680 in commissions and is paid $10.25 per hour. Javier earns $410 in commissions and is paid 12.50 per hour. What

will you find if you solve for x in the equation 10.25x + 680 = 12.5x +410.
Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

x = 120

Step-by-step explanation:

10.25x + 680 = 12.5x +410.

Subtract 10.25x from each side

10.25x-10.25x + 680 = 12.5x-10.25x +410.

680 = 2.25x +410

Subtract 410 from each side

680-410 = 2.25x +410-410

270 = 2.25x

Divide each side by 2.25

270/2.25 =2.25x/2.25

120=x

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You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte
Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \,  otherwise }} \right.

a)  We calculate  the probability that you need less than 5 minutes to get up:

P(x

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate  the probability that you will need between 8 and 13 minutes:

P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

Therefore, the probability is P(8<x<13)=0.3.

d)  We calculate the probability that you will be late to each of the 9:30am classes next week:

P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

You have 9:30am classes three times a week.  So, we get:

P=0.6^3=0.216

Therefore, the probability is P=0.216.

e)  We calculate the probability that you are late to at least one 9am class next week:

P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

Therefore, the probability is P=1.

3 0
3 years ago
Calculate the value of A please ?
Cloud [144]
A=7d+13
A=7(4)+13
A= 28+13
A=41
8 0
2 years ago
Help its hard math and i need help now
suter [353]

Answer:

A) 2(8+6)

2(14)

28

B) 2(12+4)

2(16)

32

C) 6*8

48

D) 12*4

48

3 0
3 years ago
Read 2 more answers
3.1(p - 2.7) simplified:
Mashcka [7]

3.1(p - 2.7) simplified:= 3.1p-8.37

7 0
3 years ago
Read 2 more answers
The sum of the reciprocals of two consecutive odd integers is 24/143. find the two integers.
nordsb [41]
Let one integer be x, the consecutive odd integer is x+2
reciprocals are 1/x and 1/(x+2)
1/x +1/(x+2)=24/143
make the denominators the same:
(x+2)/[x(x+2)] +x/[x(x+2)]=24/143
143(2x+2)=24(x)(x+2)
286x+286=24x²+48x
24x²-238x-286=0
use the quadratic formula: x=22 this doesn't work because 22 is not an odd number.
or x=-2.1666666666 (this is not an integer)

weird.
4 0
3 years ago
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