All categories

2 years ago

Find the surface area of the cylinder. Type an exact answer in terms of pi.

Mathematics

2 answers:

weqwewe [10]2 years ago

8 0

Answer:

154π cm²

Step-by-step explanation:

Radius (r) = 7 cm

Height (h) = 4 cm

Surface area of cylinder

= 2πr (h + r)

= 2π (7) (4 + 7)

= 2π (7) (11)

= 2π (77)

= 154π cm²

______

Hope it helps ⚜

g100num [7]2 years ago

3 0

Answer:

154π cm²

Step-by-step explanation:

Formula for the Surface Area of a Cylinder

SA = 2πr (h + r)

Solving

Here r = 7 cm and h = 4 cm
SA = 2πr (h + r)
SA = 2π × 7 (7 + 4)
SA = 14π × 11
SA = 154π cm²

You might be interested in

A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t

eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

$v=\frac{d}{t}$

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

$v-w=\frac{400mi}{2.5h}=160 mph$ (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

$v+w=\frac{400 mi}{2 h}=200 mph$ (2)

So we have two equations with two unknown variables. From (1), we get

$v=160+w$

Substituting into eq.(2)

$(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph$

So, the speed of the wind was 20 mph.

3 0

3 years ago

Read 2 more answers

Another question I need help with. I've got the part where it says to rewrite as a radical expression on my paper, but I'm havin

Alik [6]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
32^{\frac{3}{5}}\implies \sqrt[5]{32^3}\qquad 
\begin{cases}
32=2\cdot 2\cdot 2\cdot 2\cdot 2\\
\qquad 2^5
\end{cases}\implies \sqrt[5]{(2^5)^3}\implies \sqrt[5]{(2^3)^5}
\\\\\\
2^3\implies 8$

4 0

4 years ago

Angle 1 and angle 2 form a linear pair.if m angle =5x+9 and m angle 2=3x+11,find the measures of both angels.

lbvjy [14]

Answer: ∠1 = 109° ∠2 = 71°

Step-by-step explanation:

If the two angles form a linear pair, then their sum is 180°

∠1 + ∠2 = 180°

(5x + 9) + (3x + 11) = 180

8x + 20 = 180

8x = 160

x = 20

∠1 = 5x + 9

= 5(20) + 9

= 100 + 9

= 109

∠2 = 3x + 11

= 3(20) + 11

= 60 + 11

= 71

CHECK:

∠1 + ∠2 = 180°

109° + 71° = 180°

180° = 180° $\checkmark$

7 0

4 years ago

Find the limit as limit x->0, tan2x/x

kiruha [24]

We are given with the expression tan2x / x and asked to evaluate the expression to limit as theta approaches zero. In this case, we substitute first zero. The answer is zero over zero. This is indeterminate so we derive the terms accdg to L'hopital's rule. The derivative is 2 sec^2 2x/1. cos 2x is 1 so is sec^2 2x. Hence the answer is 2.

3 0

3 years ago

7. Milk chocolates cost $12.80 per pound. How much does 1 3/4 pounds cost?

Elenna [48]

Answer:

$22.4

Step-by-step explanation:

The cost of milk chocolate per pound = $12.80

= 7/4 x 12.80

= 7 x 3.2

= $22.4

Hope this helps.

5 0

3 years ago