Answer:
(3m-4/5)2
Final result :
(15m - 4)2
——————————
52
Step by step solution :
Step 1 :
4
Simplify —
5
Equation at the end of step 1 :
4
(3m - —)2
5
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 5 as the denominator :
3m 3m • 5
3m = —— = ——————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
3m • 5 - (4) 15m - 4
———————————— = ———————
5 5
Equation at the end of step 2 :
(15m - 4)
(—————————)2
5
Step 3 :
Final result :
(15m - 4)2
———
52
Step-by-step explanation:
Looking for the area of a regular figure would be taking the longest side and the shortest side and multiply
Answer:
The area in factored form is 
.
The area in standard form is 
.
Step-by-step explanation:
The area of a rectangle is length times width.
So the area here is (x+2)(x-5).
They are probably not looking for A=(x+2)(x-5) because it requires too little work.
They probably want A in standard form instead of factored form.
Let's use foil:
First x(x)=x^2
Outer: x(-5)=-5x
Inner: 2(x)=2x
Last: 2(-5)=-10
---------------------Adding together: 
.
The area in factored form is .
The area in standard form is .
Area of a circle is 75 cm².
Area of a circle is computed by multiplying pi to the square of the radius.
A = πr²
diameter = 10 cm
radius = d/2 = 10/2 = 5 cm
pi = 3
A = 3(5cm²)
A = 3(25cm²)
A = 75 cm²
Answer:
Step-by-step explanation:
The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...
DQ = (3 units)·3 = 9 units
KO = (3 units)·1 = 3 units
Then the base lengths QN and OI can be found from the Pythagorean theorem:
KI² = KO² +OI²
4² = 3² +OI²
OI = √(16 -9)
OI = √7
QN = 3·OI = 3√7
