Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
f^-1(x)=1/4x+2
Step-by-step explanation:
y=4x-8
change x and y
x=4y=8
switch sides
4y-8=x
add 8
4y=x+8
divide both sides by 4
y=1/4x+2
substitute f^-1(x) for y
f^-1(x)=1/4x+2
Answer:
estimate - 400
product - 385
Step-by-step explanation:
estimate - 77 rounds up to 80
80*5=400
product - 70*5=350
7*5=35
350+35=385
Answer:
First choice, 25
Step-by-step explanation:
200 times 1/8 = 200/8 = 25