Question

A bag contains 9 marbles: 3 are green, 2 are red, 4 are blue. Yolanda chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that the first marble is blue and the second is green?

Answer 1

Answer:  $\bold{\dfrac{1}{6}=16.67\%}$

Step-by-step explanation:

       First pick    and      Second pick

   $\dfrac{4\ blue}{9\ total\ marbles}\times\dfrac{3\ green}{8\ remaining\ marbles}\quad =\dfrac{12}{72}\quad =\large\boxed{\dfrac{1}{6}}$