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Reptile [31]
2 years ago
6

40 point question !!! If you zoom in on the pic it doesn’t have the strobe like effect !

Mathematics
1 answer:
wlad13 [49]2 years ago
4 0

Answer:

c

Step-by-step explanation:

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Help<br> Which one is for 1,2 ,and 3
Naily [24]
X-5, y+9

because -5 then positive 5 up


3 0
2 years ago
Please help :)
dangina [55]

Answer: b. 51 - 3

Step-by-step explanation:

Given, Easha has 3 less than 5 times the number of quarters (I)  that Isabelle has.

Here I is the number of quarters that Isabelle has.

Then, as per given,

Number of quarters Easha has = 5 ( number of quarters that Isabelle has) -3

= 5I-3

Hence, the  expression shows the number of quarters Easha has is "5I-3"

So the correct option is b.

7 0
3 years ago
BRAINIEST TO WHOEVER RIGHT
slava [35]

Answer:

Skewed Left

Step-by-step explanation:

5 0
2 years ago
Help?? I could really use it
Lynna [10]

Answer:

16.5 m

Step-by-step explanation:

The triangle shown in the figure is a right triangle, so we can use the Pythagoreas Theorem.

a² + b² = c²

a² + 32² = 36²

a² + 1024 = 1296

a² = 272

a = √272

a = 16.5

Answer: 16.5 m

4 0
2 years ago
One more question on this test guys. please answer as fast as possible. If you do,
GaryK [48]

1. The given rectangular equation is x=2.

We substitute x=r\cos \theta.

r\cos \theta=2

Divide through by \cos \theta

r=\frac{2}{\cos \theta}

r=2}\sec \theta

\boxed{x=2\to r=2\sec \theta}

2. The given rectangular equation is:

x^2+y^2=36

This is the same as:

x^2+y^2=6^2

We use the relation r^2=x^2+y^2

This implies that:

r^2=6^2

\therefore r=6

\boxed{x^2+y^2=36\to r=6}

3. The given rectangular equation is:

x^2+y^2=2y

This is the same as:

We use the relation r^2=x^2+y^2 and y=r\sin \theta

This implies that:

r^2=2r\sin \theta

Divide through by r

r=2\sin \theta

\boxed{x^2+y^2=2y\to r=2\sin \theta}

4. We have x=\sqrt{3}y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta\sqrt{3}

This implies that;

\tan \theta=\frac{\sqrt{3}}{3}

\theta=\frac{\pi}{6}

\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}

5. We have x=y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta

This implies that;

\tan \theta=1

\theta=\frac{\pi}{4}

\boxed{x=y\to \theta=\frac{\pi}{4}}

6 0
3 years ago
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