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3 years ago

What is the equation for the average?

Mathematics

1 answer:

Darina [25.2K]3 years ago

8 0

Answer:

D. Average = (sum of all data values) / (total number of data values)

Step-by-step explanation:

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It takes 52 minutes for 5 people to paint 5 walls.

Papessa [141]

i think its twenty hours.....but dont take my word on it im not 100% on it

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3 years ago

A box contains five keys, only one of which will open a lock. Keys are randomly selected and tried, one at a time, until the loc

Schach [20]

Answer:

Step-by-step explanation:

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3 years ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let Y = the time taken to deliver a pizza.

The random variable Y follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let X = results of a certain blood test.

It is provided that the random variable X follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to z-scores.

The z-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

4 0

3 years ago

Solve the equation for x.

elena55 [62]

Answer:

the answer is x=6 for this question

5 0

2 years ago

How to solve this part

san4es73 [151]

Try this solution (the way shown is not the shortest one):

The task on the left part:

1. note, the point P and R have coordinates (-4;-4) and (-3;-2).

2. using the coordinates of points P and R it is possible to make up the equation of the required line:

$\frac{x-x_P}{x_R-x_P} =\frac{y-y_P}{y_R-y_P}; \ => \ \frac{x+4}{-3+4}=\frac{y+4}{-2+4}; \ => \ \frac{x+4}{1}=\frac{y+4}{2} \ or \ y=2x+4$

The task of the right part:

1. note, the common view of the equation of the line is y=kx+b, where b - an intersection point of the Y-axis and the given line; k=QR/PQ.

2. according the picture b= -5, k=4/1=5, so y= -4x-5

4 0

3 years ago