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beks73 [17]
3 years ago
6

PLEASE HELL if you’re good with permutations in math 30!!! real answers only

Mathematics
2 answers:
malfutka [58]3 years ago
6 0

Answer:

10,400 or 9360

Step-by-step explanation:

I'm currently doing permutations and combinations, actually I'm finishing it. I'm doing my test rn so I'm finishing geometry today for the whole grade. So I hope I got this right:

26*4*10*10 = 10,400

26 = 26 letters possible as to be the Capital letter

4 = 4 possible special characters

10 = 10 digits are possible, unless you can't repeat numbers, then it's:

26*4*10*9 = 9360

HACTEHA [7]3 years ago
3 0

Answer:

idk

Step-by-step explanation:

ooof

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EASY TRIG - 15 POINTS
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Answer: The answers are (a) 40 cm and (b) \sin^{-1}\dfrac{23}{62}.


Step-by-step explanation: The calculations are as follows:

(a) See the figure (a). As given in the question, A circle with centre 'O' circumscribes a triangle ABC with BC = 20 cm and ∠BAC = 30°. We need to find the diameter DC of the circle.

Let us draw BD. Now, ∠BAC and ∠BDC are angles on the same arc BC, so we have

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Also, ∠CBD = 90°, since it stands on the diameter DC. So, ΔBCD will be a right angled triangle.

We can write

\sin \angle BDC=\dfrac{BC}{DC}\\\\\\ \Rightarrow \sin 30^\circ=\dfrac{20}{DC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{20}{DC}\\\\\\\Rightarrow DC=40.

Thus, the diameter of the circle = 40 cm.


(b) See the figure (b).

As given in the question, A circle with centre 'O'' circumscribes a triangle DEF with EF = 4.6 inches and diameter GF = 12.4 in.. We need to find the angle EDF.

Let us draw GE. Now, ∠EGF and ∠EDF are angles on the same arc EF, so we have

∠EGF = ∠EDF = ?

Also, ∠GEF = 90°, since it stands on the diameter GF. So, ΔGEF will be a right angled triangle.

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\sin \angle EGF=\dfrac{EF}{GF}\\\\\\ \Rightarrow \sin \angle EGF=\dfrac{4.6}{12.4}\\\\\\\Rightarrow \sin \angle EGF=\dfrac{23}{62}\\\\\\\Rightarrow \angle EGF=\sin^{-1}\dfrac{23}{62}.

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\angle EDF=\angle EGF=\sin^{-1}\dfrac{23}{62}.

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