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Vesnalui [34]
3 years ago
9

Halp me with these down belowww

Mathematics
1 answer:
Simora [160]3 years ago
3 0
For the first image it is option 4
Second image it is option 1
third image it is 3 dogs
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Zoom in to see the question do anybody know ?
olga2289 [7]

Answer:

1 or I

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
How do you solve this? <br>Y x 49/36=7/12
Triss [41]
Divide both sides by 49/36 to get y by itself:

\frac{7}{12} \div \frac{49}{36}

\frac{7}{12} \times \frac{36}{49} = \frac{254}{588}

Simplify this fraction:

\frac{254}{588} \div \frac{2}{2} = \frac{127}{294}

Now you have your answer:

y = \frac{127}{294}


5 0
3 years ago
Round 227033 to the nearest ten thousand
Sonbull [250]

I a pretty sure it is 228,000 but i am not sure.

7 0
3 years ago
Read 2 more answers
Is the point 3/5 and 4/5 corresponds to an angle in the unit circle what is the csc
Mariulka [41]

<u>Answer:</u>

csc = 5/4

<u>Step-by-step explanation:</u>

Assuming that the two given points 3/5 and 4/5 are the two sides of a triangle and a right angle 0  with legs x and y and z as its hypotenuse.

Then using Pythagoras Theorem:

z^2=x^2+y^2

z^2=(\frac{3}{5} )^2+(\frac{4}{5} )^2

z^2 = \frac{9}{25} + \frac{16}{25}

z^2=\frac{25}{25}

z^2=1

Taking square root on both the sides:

z=1

Now, sin\alpha=\frac{4}{5}

and we know that csc = \frac{1}{sin\alpha }

Therefore, csc = 5/4.

8 0
3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
3 years ago
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