<span>b • (6a2 - 3ab - 4a + 6q - 3)</span>
Answer:
For the perfect square trinomial (quadratic) i.e.
, the constant term (last term) is positive.
Step-by-step explanation:
"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.
For example:
![\left(x\:+\:3\right)^2](https://tex.z-dn.net/?f=%5Cleft%28x%5C%3A%2B%5C%3A3%5Cright%29%5E2)
![\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3APerfect%5C%3ASquare%5C%3AFormula%7D%3A%5Cquad%20%5Cleft%28a%2Bb%5Cright%29%5E2%3Da%5E2%2B2ab%2Bb%5E2)
![a=x,\:\:b=3](https://tex.z-dn.net/?f=a%3Dx%2C%5C%3A%5C%3Ab%3D3)
![=x^2+2x\cdot \:3+3^2](https://tex.z-dn.net/?f=%3Dx%5E2%2B2x%5Ccdot%20%5C%3A3%2B3%5E2)
![=x^2+6x+9](https://tex.z-dn.net/?f=%3Dx%5E2%2B6x%2B9)
Therefore, for the perfect square trinomial (quadratic) i.e.
, the constant term (last term) is positive.
<span> first, write the equation of the parabola in the required form: </span>
<span>(y - k) = a·(x - h)² </span>
<span>Here, (h, k) is given as (-1, -16). </span>
<span>So you have: </span>
<span>(y + 16) = a · (x + 1)² </span>
<span>Unfortunately, a is not given. However, you do know one additional point on the parabola: (0, -15): </span>
<span>-15 + 16 = a· (0 + 1)² </span>
<span>.·. a = 1 </span>
<span>.·. the equation of the parabola in vertex form is </span>
<span>y + 16 = (x + 1)² </span>
<span>The x-intercepts are the values of x that make y = 0. So, let y = 0: </span>
<span>0 + 16 = (x + 1)² </span>
<span>16 = (x + 1)² </span>
<span>We are trying to solve for x, so take the square root of both sides - but be CAREFUL! </span>
<span>± 4 = x + 1 ...... remember both the positive and negative roots of 16...... </span>
<span>Solving for x: </span>
<span>x = -1 + 4, x = -1 - 4 </span>
<span>x = 3, x = -5. </span>
<span>Or, if you prefer, (3, 0), (-5, 0). </span>
Answer:
Step-by-step explanation:
202 students taking math and are business majors
only math, would be (861 - 202) = 659
only business majors, would be (525 - 202) = 323
so there are (659 + 323) = 982 that are math or business majors
Answer:
6ab(2a-3b-5b²)
Step-by-step explanation:
6(2a²b-3ab²-5ab³)
6a(2ab-3b²-5b³)
6ab(2a-3b-5b²)