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Vinil7 [7]
3 years ago
15

Planes Q and R intersect. Lines d and c are vertical on plane R and form a right angle with line B on plane Q. Line B is horizon

tal on plane Q. Line a is slightly diagonal on plane Q.
In the diagram, the only figure that could be parallel to line c is

line a.
line b.
line d.
plane Q.
Mathematics
2 answers:
zmey [24]3 years ago
6 0

Answer:

C. Line D

Step-by-step explanation:

Just took the test and got it right

Akimi4 [234]3 years ago
4 0

Answer:

C. line d

Step-by-step explanation:

Two parallel lines are lines that do not meet even with continuous extension of their length. While two lines are perpendicular when they form a right angle to each other at the point where they meet.

In the given question, the only figure that would be parallel to line c is line d. Line a is not parallel to line c (since it is slightly diagonal, it would intersect line c at a point) and line B is perpendicular to line c (since it is horizontal to plane Q), same as plane Q. So that lines c and d are parallel to each other.

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Answer:

c =  \sqrt{146}   \\ x = 48°

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(15 Points!!!) What is the length of side A in centimetres?<br> A. 1/6<br> B. 1/2<br> C. 2<br> D. 6
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The length of side A in centimeters is 6cm

D. 6

3 0
3 years ago
Prove that the statement (ab)^n=a^n * b^n is true using mathematical induction.
mamaluj [8]

Answer:

see below

Step-by-step explanation:

      (ab)^n=a^n * b^n

We need to show that it is true for n=1

assuming that it is true for n = k;

(ab)^n=a^n * b^n

( ab) ^1 = a^1 * b^1

ab = a * b

ab = ab

Then we need to show that it is true for n = ( k+1)

or (ab)^(k+1)=a^( k+1) * b^( k+1)

Starting with

  (ab)^k=a^k * b^k    given

Multiply each side by ab

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Therefore, the rule is true for every natural number n

5 0
3 years ago
Read 2 more answers
. Find the sum of the geometric sequence. (1 point) 1, one divided by four, one divided by sixteen, one divided by sixty four, o
il63 [147K]

Answer:

0.332

Step-by-step explanation:

given series

1/4, 1/16,1/64.1/256

this is geometric series

where common ratio   r is given by

nth term/ (n-1)th term

let the second term is nth term and first term is (n-1)th term

r = 1/16 / (1/4) = 1/4

___________________________________________

sum of series is given by

a (1-r^n)/1-r

where a is first term

n is the number of terms

r is the common ration

___________________________________________

in the given series

1/4, 1/16,1/64.1/256

a = 1/4

r = 1/4

n = 4

thus ,

sum = 1/4(1-(1/4)^4)/ (1-1/4)

sum = 1/4(1-(1/256)/(4-1)/4

sum = 1/4((256-1)/256 / 3/4

1/4 in numerator and denominator gets cancelled

sum =( 255/256*3) = 255/768 = 0.332

Thus, sum of series is 0.332.

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4 years ago
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