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lord [1]
3 years ago
6

Rick buys a spatula costing $2.23. He gives the cashier $5.00. The cashier gives him his change using the least number of coins

and bills possible. How many of each coin or bill does he receive?
Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

2 Dollar Bills

3 quarters

2 pennies

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A)<br> 2x + y - 12 = 0<br> x + y + 3 = 0
AVprozaik [17]

Answer:

x=15   and   y= -18

Step-by-step explanation:

2x + y - 12 = 0            Equation 1

x + y + 3 = 0                Equation 2

From two given equations, we can find the value of both x and y by finding the value of one variable from any one of the two equations in terms of other variable and putting it to other equation.

Solving equation 1

Finding 'y' in terms of 'x'           2x+y=12\\y=12-2x                 Equation 3

Putting above equation in equation 3 in 2

                                       x + y + 3 = 0

                                      x+12-2x+3=0

                                         x=15

Putting value of 'x' in equation 3 to find the value of 'y'

                                      y=12-2(15)\\y=12-30\\y= -18

6 0
3 years ago
Three men have 9 bottles. How many do each man get?
ra1l [238]
 When you divide 9 by 3, you get three. You can distribute three bottles each to every man. 
6 0
4 years ago
Read 2 more answers
Match the function in the left column with its period in the right column.
kiruha [24]

The results for the matching between function and its period are:

  • Option 1 - Letter D
  • Option 2 - Letter A
  • Option 3 - Letter C
  • Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi

Thus, the option 1 matches with the letter D.

2) Option 2

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}

Thus, the option 2 matches with the letter A.

3) Option 3

\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi

Thus, the option 3 matches with the letter C.

4) Option 4

\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0
2 years ago
If x= 3 and y=2, evaluate the following<br>expressions <br>io 2xt 3y​
kirza4 [7]

helli I kaiahaahajkasn

Step-by-step explanation:

helli I kaiahaahajkasn

7 0
4 years ago
Read 2 more answers
1-7x-7=15 Solve Please I don't know.
DIA [1.3K]

Answer:

Step-by-step explanation:

So first we combine like terms on the left

1-7=-6

then we have

-7x-6=15

next we add 6 both sides

-7x-6=15

   +6   +6

-7x=21

then we divide -7 each side

we get

x=-3

4 0
3 years ago
Read 2 more answers
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