Three coins are flipped,what is the Probability of getting one HEAD and two TAILs?

Which of the following graphs shows the preimage P(x)=x^2 and the image I(x)=P(1/3x)?

Ksju [112]

Answer:

The picture with the widest graph in red

Step-by-step explanation:

The graph P(x) is the parent graph for all quadratic functions. It has a vertex of (0,0) and has the following points:

x f(x)

-2 4

-1 1

0 0

1 1

2 4

The image of l(x) = P(1/3x) changes the points of the function to

x f(x)

-2/3 4/9

-1/3 1/9

0 0

1/3 1/9

2/3 4/9

This makes the graph much wider. The graph with the widest red graph is the graph.

7 0

4 years ago

Read 2 more answers

Someone please answer this and try hard. I selected the highest amount of points to give. It was 90, but it doesn't always come

azamat

Volume of a cylinder = PI x r^2 x H

r = 4 so r^2 = 4^2 = 16

h = 3

Volume = 3.14 x 16 x 3 = 150.72 ft^3

it doesn't say how to round the answer so you may need to round it

5 0

3 years ago

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When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

7 0

3 years ago

Ms. Patterson burns 236 calories riding her bike every hour. She wants to burn more than 590 calories riding her bike at the sam

Alekssandra [29.7K]

Ms. Patterson will take t>2.5 hours to burn 590 calories riding her bike at the same rate which is 236 calories every hour.

<h3 /><h3>What amount of time Ms. Patterson will take to burn more then 590 ?</h3>

Given that -

she burns 236 calories in 1 hour get = $\dfrac{1}{236}$ hours

so time taken to burn 590 calories at same rate = $590 \times\dfrac{1}{236}$ hours

so time taken to burn 590 calories at same rate = 2.5 hours

hence Ms. Patterson will take t>2.5 hours to burn 590 calories riding her bike at the same rate which is 236 calories every hour.

To know more about follow

brainly.com/question/14733838

3 0

2 years ago

The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V

aleksklad [387]

Answer:

The answer is explained below

Step-by-step explanation:

Given that The volume of air inside a rubber ball with radius r can be found using the function V(r) = $\frac{4}{3}\pi r^3$ , this means that the volume of the air inside the rubber ball is a function of the radius of the rubber ball, that is as the radius of the rubber ball changes, also the volume of the ball changes.

As seen from the function, the radius is directly proportional to the volume of the ball, if the radius increases, the volume also increases.

$V(\frac{5}{7} )$ is equal to the volume of the ball when the radius of the ball is $\frac{5}{7}$ . Therefore:

$V(\frac{5}{7} )=\frac{4}{3} \pi *(\frac{5}{7} )^3=1.53\ unit^3$

3 0

3 years ago