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Fittoniya [83]
3 years ago
13

NEEEEEDDDD HELLLLPPPPP PLEASEEEEEE!!!!! I will mark brainiest!!!!!

SAT
2 answers:
nikdorinn [45]3 years ago
8 0
1: C
2: C
3: A
4: B
5: A
6: D
7: C
8: D
9: C
10: B
11: A
12: B
13: D
It would be so great if you could mark brainiest and I hope this helps :)
Softa [21]3 years ago
6 0
Too much work bud I’m just trying to get my points if I could I would answer but I am not the smartest :)
You might be interested in
find the area under the standard normal curve that lies outside the interval between z=-2.73and z=-1.39
Natasha_Volkova [10]

Answer:

0.9209

Explanation:

For a  normally distributed random variable,  the only way to find areas is using the z score. The z score is given by the equation:

z=\frac{x-\mu}{\sigma}

Where μ is the mean, σ is the standard deviation and x is the raw score to be measured.

The area under the standard normal curve that lies between the interval z=-2.73 and z=-1.39

From the z table, Area between -2.73 and -1.39 = P(z < -1.39) - P(z < -2.73) = 0.0823 - 0.0032 = 0.0791

Since the Area between -2.73 and -1.39 is 0.0791, the are outside the interval = 1 - 0.0791 = 0.9209

4 0
3 years ago
which inequality models this problem? josephine started a business selling cosmetics. she spent $4500 to obtain her merchandise,
Alenkinab [10]

Answer:

Here u go lil bro,

550w>4500+200w

Explanation:

Since she earns $550 per week, Josephine's earnings can be represented as 550w, where w is the number of weeks.

Her costs are $200 per week, or 200w, plus the 4500 start up costs; this gives us 200w+4500.

We want a profit; this means the amount she earns, 550w, must be greater than the costs, 200w+4500:

550w > 200w + 4500, or

550w > 4500 + 200w

3 0
3 years ago
Read 2 more answers
A typical neutron star has a mass of about 1. 5msun and a radius of 10 kilometers
Triss [41]

How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

<h3>Density of the Neutron star</h3>

Density

ρ = m / V

Where:

ρ= density

m = mass of the planet 5.98 10²⁴ km

V =volume of the spherical layer

Volume of a sphere

Volume = 4/3 π r³

Mass = 1.5 = 1.5 1,991 10³⁰

Mass= 2.99 10³⁰ kg

Density:

ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]

ρ is = 7.13 10 17 kg / m³

V = 5.98 10²⁴ / 7.13 10¹⁷

V = 8,387 10⁶ m³

Thickness of the layer

V = 4π r² e

e = V / 4π r

e = 8,387 10⁶ / [4π (10 10³)²]

e = 6.67 10⁻³ m

Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

Learn more about Density of the Neutron star here:brainly.com/question/15700804

3 0
2 years ago
Referring to the same number 7, if m
Flura [38]

Answer:

7m

Explanation:

7.m

3 0
2 years ago
The rock cycle forms new rocks using which of the following processes? a. Crystallization c. Erosion b. Compaction d. All of the
kozerog [31]

Answer:

The rock cycle describes how rocks change as a result of natural processes. The rock cycle forms new rocks using the crystallization, erosion and compaction processes. This makes the correct answer: D: all of the above. Igneous rocks for example are rocks formed from the crystallization( formation of rock crystals in cooling magma) of a liquid. Sedimentary rocks are formed by erosion. However, in order to form a sedimentary rock, the accumulated sediment must become compacted and cemented together.

4 0
2 years ago
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