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3 years ago

5. How can a teacher help children who have articulation problems?

1 answer:

3 0

A way a teacher can help the student by using preferential seating, so that the student can see the teacher's mouth when he/she is speaking. Reduce background noise in the classroom. Use preferential seating, so that the teacher can more privately model correct articulation to the student. Give additional time for the student to speak. This way the child will have an easier time learning.

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You can buy DVDs at a local store for 15.59 each. You can buy them at on online store for 13.99 each plus $6 shipping. How many

dalvyx [7]

Local(L) = 1 x (15.99)
Online(O) = (1 x 13.99) + 6

So use that equation until you find the same number.

L1=15.99
O1=19.99

L2=31.98
O2=33.98

L3=47.97
O3=47.97

And your answer will be three from local and three from online.

8 0

3 years ago

What is-3/7x-2 in standard form

Eddi Din [679]

If you are given y = (-3/7)x - 2 and you want it in the form Ax+By = C, then...

y = (-3/7)x-2
7*y = 7*( (-3/7)x-2) ... multiply both sides by 7
7y = -3x-14 ... distribute and multiply
7y+3x = -3x-14+3x ... add 3x to both sides
3x+7y = -14

The standard form equation is 3x+7y = -14

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4 years ago

A nursery owner buys 9 panes of glass to fix some damage to her greenhouse. The 9 panes cost

Nadya [2.5K]

Answer: $11.80 for another 4 panes of glass.

Step-by-step explanation: We know that 9 panes of glass cost $26.55, but we should first find how many dollars would it cost per pane of glass, or 1.

So, we can divide 26.55 by 9 to find the price per 1 pan of glass.

26.55/9 = 2.95, or $2.95 per pane of glass.

Now, we want to know how much it will cost for 4 panes of glass. Simply multiply 2.95 by 4.

2.95 x 4 = 11.8, or $11.80 for another 4 panes of glass.

8 0

3 years ago

Read 2 more answers

Tyler owned the librarian late fees he had to pay a 3% fee on the cost of the books, which was $35.62. What was he charged for a

Marysya12 [62]

Answer:

$1.07 for the late fees.

Step-by-step explanation:

You can find the fee for this price by finding 3% of the $35.62 (total cost of the books). You can find this number by multiplying (35.62*.03).

35.62*.03

1.0686

Round up because you cannot have part of a cent.

$1.07 for the late fees.

4 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

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3 years ago