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amid [387]
3 years ago
7

Solve 4+x>6 graph the solution

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer: The solution is x>2.

Step-by-step explanation: Move all terms not containing x to the right aide of the inequality. I have attached a picture of the graph as well ☆

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What is the product of all non- zero integers between -6 and 4
deff fn [24]
The product is -720.

Below is the list of non-zero integers between -6 and 4:

-5, -4, -3, -2, -1, 1, 2, 3

and the product of all these numbers would be -720.
4 0
3 years ago
Find a function for the graph below.
Nastasia [14]

\qquad\qquad\huge\underline{{\sf Answer}}♨

The given function has Amplitude of 3, and by seeing it we can conclude that it's a sine function.

Therefore, we can conclude that the required Answer is ~

\qquad \sf  \dashrightarrow \:c. \: f(t) = 3 \sin(4t)

6 0
2 years ago
thank you for hurrying here is the very last one Explain how you would find the perimeter of this triangle.
Lena [83]

Step-by-step explanation:

Use the method of TOA CAH SOH.

tan(51.3) =  \frac{opp}{adj}  \\  \tan(51.3)  =  \frac{u}{4}  \\ u = 4 \tan(51.3)

cos(51.3)  =  \frac{adj}{hypo}  \\  \cos(51.3)  =  \frac{4}{v}  \\ v \cos(51.3)  = 4 \\ v =  \frac{4}{ \cos(51.3) }

Perimeter of triangle = Sum of all sides =

u \:  +  \: v + 4

5 0
3 years ago
Read 2 more answers
Please help me find the y-intercept! :(
zvonat [6]
5 inches

Explanation: y = Mx + b, m is your slope (1/2), b is your y-intercept (5 inches)

Equation would be y= (1/2)x + 5
4 0
3 years ago
The volume of a rectangular prism is b^3 + 8b^2 + 19b + 12 cubic units, and its height is b + 3 units.
BlackZzzverrR [31]
The answer is (b² + 5b + 4).

The volume of a rectangular prism (V) is:
V = l · w · h              (l - length, w - width, h - height)

The base of the rectangular prism is the product of length and width, so the area of the base is:
A = l · w

Since V = l · w · h and A = l · w, then:
V = A · h
It is given:
V = b³ + 8b² + 19b + 12
h = b + 3
⇒ b³ + 8b² + 19b + 12 = A · (b + 3)
⇒ A = (b³ + 8b² + 19b + 12) ÷ (b + 3)

Now, we have to present the volume as multiplication of factors. One of the factors is b+3. So:
b³ + 8b² + 19b + 12 = (b · b² + 3b²) + (5b² + 15b) + (4b + 3·4) =
                                =    b²(b + 3)    +   5b(b + 3)   +  4(b + 3) =
                                = (b + 3)(b² + 5b + 4)

A = (b³ + 8b² + 19b + 12) ÷ (b + 3) = (b + 3)(b² + 5b + 4) ÷ (b + 3)

(b + 3) can be cancelled out:
A = (b² + 5b + 4)
7 0
3 years ago
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