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NeX [460]
3 years ago
12

The measure of b is..

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0

Answer:

b =21

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a  and b are the legs and c is the hypotenuse

20^2 + b^2 = 29^1

400 + b^2 =841

Subtract 400 from each side

b^2 = 441

Take the square root of each side

sqrt(b^2) = sqrt(441)

b =21

ra1l [238]3 years ago
7 0

Answer:

b = 21

Step-by-step explanation:

Ok so solving this is actually really simple.

We need to use the Pythageorum Theorum formula which is a^2+b^2=c^2.

So we already know the c and b which are 29 and 20 and we are trying to find b or a in the formula so.

We have to plug the numbers 29 and 20 into the formula and do the steps which is to sqaure them. So 29 and 20 squared are 841 and 400.

So we have to plug those numbers into the formula and it looks like this now a^2+400=841. So now we have to get a squared alone and to do tha we subtract 400 from 841 which is 441. So now to find a we have to find the square root of a and 441 which is a and 21 so b is 21.

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3 years ago
How many zeros will the product of 700 and 300 have?
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4 0
4 years ago
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if i have a known points of polynomial(2,5),(3,2) and (4,5). what would be the polynomial function will be?
faltersainse [42]
I think you mean "if the points <span>(2,5), (3,2) and (4,5) satisfy an unknown 3rd degree polynomial, what is the polynomial?"

Since 3 roots {2, 3, 4} are known, we might begin by assuming that this poly would have the form y = ax^3 + bx^2 +  cx + d (which has three factors).  Unfortunately, three roots are not enough to determine all four constants {a, b, c, d}.

So, let's assume, instead, that the poly would have the form y = ax^2 + bx + c.  Three given points should make it possible to determine {a, b, c}.

(2,5):  5 = a(2)^2 + b(2) + c => 5 = 4a + 2b + c

(3,2):  2 = a(3)^2 + b(3) + c   => 2 = 9a + 3b + 5 - 4a - 2b

(4,5):  5 = a(4)^2 + b(4) + c   => 5 = 16a + 4b + 5 - 4a - 2b

Now we have two equations in a and b alone, which enables us to solve for a and b:

</span>2 = 9a + 3b + 5 - 4a - 2b becomes -3 = 5a + b
<span>and 
</span>5 = 16a + 4b + 5 - 4a - 2b becomes 0 = 12a + 2b, or 0 = 6a + b, or 0=-6a-b
<span>
Adding this result to -3 = 5a + b, we get -3 = -a, so a =3.
Thus, since -3 = 5a + b, -3 = 5(3) + b, so b = -18

All we have to do now is to find c.  Let's do this using </span>5 = 4a + 2b + c.
We know that a = 3 and b = -18, so  this becomes   5 = 4(3) + 2(-18) + c.

Thus, 5 = 12 - 36 + c, or c = 29.

With a, b and c now known, we can write the poly as y = 3x^2 - 18x + 29.

Now the only thing to do remaining is to verify that each of the three given points satsifies        y = 3x^2 - 18x + 29.  Try this, please.



5 0
4 years ago
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