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Mashutka [201]
3 years ago
5

Can someone explain to me how to do this please

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

look at the attachment (p.s you could also use desmos to find the vertex)

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How do you subtract an integer from another integer without using a number line or counters? Give an example.
Feliz [49]
An integer is all whole numbers and zero, are the numbers you are talking about negatives?
3 0
4 years ago
The base of a triangle is 7 inches more than 4 times the height. If the area of the triangle is 93 square inches, find the base
Galina-37 [17]

Answer:

Step-by-step explanation:

Let the height = h

Let the base = 4h + 7

Area of a triangle = 1/2 * b * h

Area = 93 square inches

1/2 * (4h + 7)* h = 93            Multiply both sides by 2

(4h + 7) * h = 93*2

(4h + 7)*h = 186                    Remove the brackets

4h^2 + 7h = 186                   Subtract 186 from both sides.

4h^2 + 7h - 186 = 0

Use the quadratic formula to solve

a = 4

b = 7

c = - 186

x1 = (-7 + sqrt(7^2 - 4*4*(-186) ) /2*4

x1 = (-7 + sqrt(49 - 16*(-186)) / 8

x1 = (-7 + sqrt(49 + 2976)) / 8

x1 = (-7 + sqrt(3025)) / 8

x1 = (-7 +55 ) / 8

x1 = (48)/8

x1 = 6

There is another root, but it has to be minus and therefore cannot be used as a length. x2 = - 7.75

h = 6

b = 4*6 + 7 = 31

Check

Area = 1/2 * b * h

Area = 1/2 * 31 * 6

Area = 1/2 *186

Area = 93 which is what we were given so the answer is correct.

4 0
2 years ago
Show step by step work ​
SOVA2 [1]

Answer:

$60

Step-by-step explanation:

Movieland is in yellow....at the far left the Moviland- yellow 'regular' price for a DVD is shown as   y= $20

three of these would be  3 x $20 = $60

3 0
2 years ago
Prove that sin^4x + cos^4x= sinxcosx
yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

sin^4(x) + cos^4(x)

We can rewrite this as:

(sin^2(x))^2 + (cos^2(x))^2

Now we can add and subtract cos^2(x)*sin^2(x) to get:

(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)

We can complete squares to get:

(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2

and we know that:

cos^2(x) + sin^2(x) = 1

then:

1 - 2*sin(x)^2*cos(x)^2

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

1 - \frac{sin^2(2*x)}{2}

Then the simplification is:

cos^4(x) + sin^4(x)  = 1 - \frac{sin^2(2*x)}{2}

7 0
3 years ago
Solve the equation and state the value of x<br>w - 2 = -8- 5w​
Wewaii [24]

Answer:

x=-1

Step-by-step explanation:

w-2=-8-5w

-2=-8-6w

+8 +8

6=-6w

divide 6 in both side

x=-1

hope this help.

4 0
3 years ago
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