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marshall27 [118]
2 years ago
11

2/5×3/7+3/10+1/14×2/5​

Mathematics
2 answers:
Irina-Kira [14]2 years ago
4 0

The answer is 1/2

please see the attached picture for full solution

Hope it helps

Ad libitum [116K]2 years ago
3 0

Answer:

=  \frac{1}{2}

Step-by-step explanation:

\frac{2}{5}  \times  \frac{3}{7}  +  \frac{3}{10}  +  \frac{1}{14}   \times  \frac{2}{5}  \\  =  \frac{6}{35}  +  \frac{3}{10}  +  \frac{2}{70}  \\  =  \frac{12 + 21 + 2}{70}  \\  =  \frac{35}{70}  \\  =  \frac{1}{2}

hope this helps

brainliest appreciated

good luck! have a nice day!

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If each foot of water in a lake screens out 60% of the light above, what percent of the light passes through 5 feet of water?
BartSMP [9]
The amount of light passing through each foot the water in the lake = 100% - 60% = 40%
The percent of light passing through 5 feet of water = 0.4^5 = 0.01024 = 1.02%
8 0
3 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
2 years ago
Read 2 more answers
MARKING BRAINLEST!!!!!!!!!
lapo4ka [179]

Answer:

A  3^4 * 3^-4 / 3^6

C 1 / 3^6

Step-by-step explanation:

( 3^2 * 3^-2)

-------------------  all the the power of 2

           3^3

First simplify the numerator

We know a^b* a^c = a^(b*c)

( 3^(2+-2))

-------------------  all to the power of 2

           3^3

( 3^(0))

-------------------  all to the power of 2

           3^3

( 3^(0))

-------------------  all to the power of 2

           3^3

We know a^b/ a^c = a^(b-c)

3^(0-3)  all to the power of 2

3^-3 all to the power of 2

3^-3 ^2

We know that a^b^c = a^(b*c)

3^(-3*2)

3^ -6

We know the negative exponent takes if from the numerator to the denominator

1 / 3^6

The other correct choice is A

3^4 * 3^-4 = 3^0 which is 1

1/3^6 is the same answer

8 0
3 years ago
Read 2 more answers
Solve for x<br>Please HELPPPPPPPPPPPPPPPPP ME ILL GIVE YOU BRAINLY
valina [46]
<h3>Answer:</h3>

x = 2

<h3>Explanation:</h3>

The rule for secants is that the product of segment lengths (on the same line) from the point of intersection to the points on the circle is a constant for any given point of intersection. Here, that means ...

... 3×(3+5) = 4×(4+x)

... 6 = 4+x . . . . divide by 4

... 2 = x . . . . . . subtract 4

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<em>Comment on this secant relationship</em>

Expressed in this way, the relationship is true whether the point of intersection is inside the circle or outside.

5 0
3 years ago
Read 2 more answers
I need help . This problem is confusing me.<br><br>​
Sholpan [36]

Answer:

The answer is 3093.

3093 (if that series you posted actually does stop at 1875; there were no dots after, right?)

Step-by-step explanation:

We have a finite series.

We know the first term is 48.

We know the last term is 1875.

What are the terms in between?

Since the terms of the series form a geometric sequence, all you have to do to get from one term to another is multiply by the common ratio.

The common ratio be found by choosing a term and dividing that term by it's previous term.

So 120/48=5/2 or 2.5.

The first term of the sequence is 48.

The second term of the sequence is 48(2.5)=120.

The third term of the sequence is 48(2.5)(2.5)=300.

The fourth term of the sequence is 48(2.5)(2.5)(2.5)=750.

The fifth term of the sequence is 48(2.5)(2.5)(2.5)(2.5)=1875.

So we are done because 1875 was the last term.

This just becomes a simple addition problem of:

48+120+300+750+1875

168      +   1050  +1875

          1218          +1875

                         3093

6 0
3 years ago
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