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steposvetlana [31]

3 years ago

13

The PS5 is set to release this year. It will cost $600 but the price will drop by 7.5% per year. How much will a PS5 cost in 202

5?

2 answers:

Morgarella [4.7K]3 years ago

4 0

Okay, so the formula for these types of problems is $yab^x$ I believe, or something like that.

So the price is 600 for y, 1-0.0075 is the b because it is decreasing in value each year, and it is 5 years from now, so 5 for the x.

Plug those in, and you will get about 577.83.

I hope this helps.

Zarrin [17]3 years ago

3 0

Answer: 562.5

Step-by-step explanation:

Ok...Im <em>PRETTY </em>sure this is right, because you multiply 5 (5 years till 2025) times 7.5 (the rate of decrease in price) and subtract that from 500, so that would be 600-37.5, which gives you 562.5

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Answer:

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2 years ago

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Nico owns 11 instructional piano books. Two are beginner books, six are intermediate books, and three are advanced books. If two

Leona [35]

The probability that he first chooses an advanced book and then chooses a beginner book is 6/121.

<h3>Probability</h3>

Given:

Beginner book=2

Intermediate book=6

Instructional piano books=11

Advanced books=3

Hence:

Probability=(2×3)÷(11×11)

Probability=6/121

Therefore the probability that he first chooses an advanced book and then chooses a beginner book is 6/121.

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7 0

1 year ago

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7. Are the ordered pairs below an arithmetic sequence or geometric

DochEvi [55]

Answer:

8. Arithmetic Progression

9. $f(9) = 300$

Step-by-step explanation:

Given

$\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}$

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

$d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3$

This gives:

$d = 45 - 55 = 35 - 45 = 25 - 35$

$d = -10 = -10 = -10$

$d=-10$

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

$f(n) = f(1) + f(n-1)$

To find f(9), we substitute 9 for n

$f(9) = f(1) + f(9-1)$

$f(9) = f(1) + f(8)$

We need to solve for f(8); substitute 8 for n

$f(8) = f(1) + f(8 - 1)$

$f(8) = f(1) + f(7)$

We need to solve for f(7); substitute 7 for n

$f(7) = f(1) + f(7 - 1)$

$f(7) = f(1) + f(6)$

We need to solve for f(6); substitute 6 for n

$f(6) = f(1) + f(6 - 1)$

$f(6) = f(1) + f(5)$

We need to solve for f(5); substitute 6 for n

$f(5) = f(1) + f(5 - 1)$

$f(5) = f(1) + f(4)$

From the function, f(4) = 25 and f(1) = 55.

So:

$f(5)=55 + 25$

$f(5)=80$

$f(6) = f(1) + f(5)$

$f(6) = 55 + 80$

$f(6) = 135$

$f(7) = f(1) + f(6)$

$f(7) = 55 + 135$

$f(7) = 190$

$f(8) = f(1) + f(7)$

$f(8) = 55 + 190$

$f(8) = 245$

$f(9) = f(1) + f(8)$

$f(9) = 55 + 245$

$f(9) = 300$

8 0

3 years ago

Which shows how to solve the equation Three-fourths x = negative 6 for x in one step?

tino4ka555 [31]

Answer:

x = -8

Step-by-step explanation:

Let's put this into numbers: $\frac{3}{4}$ x =-6

The first thing you want to do is to multiply both sides by 4:

3x=-24

Next you need to divide by 3:

x=-8

The answer is -8

5 0

3 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago