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Setler [38]
4 years ago
6

Which statement describes the graph of this polynomial function?

Mathematics
2 answers:
asambeis [7]4 years ago
6 0

Answer: C. The graph crosses the x-axis at x=-2 and x=1 & touches the x-axis at x=0

Step-by-step explanation:

You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.

f(x) = x^4 + x^3 - 2x^2

Since each term has at least x^2, we can factor it out.

f(x) = x^2(x^2 + x - 2)

Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.

f(x) = x^2(x + 2)(x - 1)

Now we can also separate the x^2 into 2 x's.

f(x) = (x)(x)(x + 2)(x - 1)

To find the zeros, we need to set them all equal to 0

x = 0

x = 0

x + 2 = 0

x = -2

x - 1 = 0

x = 1

Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.

fgiga [73]4 years ago
5 0

Answer:

Third option or option C Edge2020

Step-by-step explanation:

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Two functions are given.
ArbitrLikvidat [17]

Hi

f(x) = g(x)   if    -x²+3x-2   - ( -x+1) = 0

                      -x² +3x-2 +x-1 = 0

                      -x² +4x -3 = 0

To solve, tou have to use the general method of resolution of a quadratic fonction.  

To determine if it's has a solution in R, let's calculate  Δ

Δ = (4)² - 4 * (1) *(-3)

Δ = 16 +12

Δ= 28  

as Δ≥ 0  so  the function allow two solution within R  

so S 1 =  ( -4 +√28) / 2            S 2 =   (-4 -√28 ) /2

    S1 =   ( -4 + 2√7) /2            S2 =    (-4 - 2√7) /2

    S1 =    (2 (-2 +√7) /2            S2      2 (-2 -√7)   /2

    S1 =    -2 +√7                       S2 =      -2 -√7

So the two function  are equal   twice. one  for   x = -2 +√7  and second x = -2-√7

4 0
3 years ago
If (2 − 3i) + (x + yi) = 6, what is x + yi?<br><br> i really need help with these
ra1l [238]
I hope this helps you


2-3i+x+yi =6+0.i


2+x-i(3-y)=6+0.i


2+X=6


X=4


i(3-y)=0.i


Y=3


x+y.i


4+3i
8 0
4 years ago
Read 2 more answers
If (x+2) is a factor of x^3-6x^2+kx+10, k=
tensa zangetsu [6.8K]
If a polynomial is divisible by x-a, then a is a root of this polynomial.
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(-2)^3-6 \times (-2)^2+ k \times (-2)+10=0 \\&#10;-8-6 \times 4-2k+10=0 \\&#10;-8-24-2k+10=0 \\&#10;-2k-22=0 \\&#10;-2k=22 \\&#10;\boxed{k=-11}
5 0
4 years ago
10 points plz answer thx
amid [387]

Answer:

(   \sqrt[4]{81} ) {}^{3}

81 {}^{ \frac{1}{4}  \times 3}

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3 0
3 years ago
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a vector has a magnitude of 50 in the 35º direction. what are the horizontal and vertical components of this vector?
Semenov [28]

Answer:

Horizontal component: 40.95

Vertical component: 28.67

Step-by-step explanation:

To find the horizontal and the vertical component of this vector, you need:

The formula for calculate the horizontal component:

a_x=|a|cos\alpha

Where |a| is the magnitude

The formula for calculate the vertical component:

a_y=|a|sin\alpha

Where |a| is the magnitude

Given the angle 35 degrees and the magnitude,you can substitute values into the formulas.

Therefore, you get  that the horizontal component and the vertical component of this vector are:

a_x=50cos(35\°)=40.95

a_y=50sin(35\°)=28.67

7 0
3 years ago
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