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Paraphin [41]
3 years ago
11

Write equation in function form y-3x-11=0

Mathematics
1 answer:
Basile [38]3 years ago
8 0
y-3x-11=0 \ \ | \ add\ 3x\ and \ 11\ to\ both\ sides \\\\y=3x+11


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Solve, show all four steps.
Eva8 [605]
3x-6+10x+15=35
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13x=26
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4 0
2 years ago
Understanding the Number of Solutions Miriam works more than 40 hours a Find the solutions of the inequality and complete the st
arsen [322]

Answer:

The solutions of the inequality include all numbers greater than 40.  

There are an infinite number of the inequality.

Step-by-step explanation:

6 0
3 years ago
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Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

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we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
2 years ago
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Wewaii [24]

Answer:

The value of x>-10

Step-by-step explanation:

The interval notation if you need it is (-10,♾)

3 0
3 years ago
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12 divided by 5/6 (pretty easy but im lazy)&lt;3
Mumz [18]

Answer:

14.4

Step-by-step explanation:

Hope this helps you :)

6 0
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