When you illustrate the problem, it would look like the diagram shown in the picture. There are pictures, each with a length of 6 inches, that are placed all around the perimeter. To solve the number of pictures, the solution is as follows:
Size of picture = 6 inches * 1 ft/12 inches = 0.5 ft/picture
Pictures along the length = 7 ft * 1 picture/0.5 ft = 14 pictures
Pictures along the width = 4 ft * 1 picture/0.5 ft = 8 pictures
Since perimeter is 2L + 2W, the total number of pictures is:
Total pictures = 2(14) + 2(8) = 44 pictures
Answer:
8 cans of frozen dinner
9 cans of soup
Step-by-step explanation:
Given:
200mg/1 can of soup
600mg/1 can of frozen dinner
17 cans of both soup and frozen dinners which contain 6600mg
200 (9) + 600 (8) = 6600
Answer:
The first and third quartiles were calculated incorrectly. Also, this means the inter quartile range is incorrect.
Step-by-step explanation:
The first quartile is going to be the median of the lower half of the data set {89, 93, 99, 110} this median is (93+99)/2, or 96.
The third quartile can be calculated the same way with the data set {135, 144, 152, 159} This gives us 148 as the third quartile.
Lastly, the interquartile range is just the difference between the first and third quartiles, which is 52.