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zalisa [80]
2 years ago
7

In ordered pair (6,-2), starting from the origin, you'd move...

Mathematics
2 answers:
stiks02 [169]2 years ago
8 0
You’d move 6 to the right and 2 down
sweet-ann [11.9K]2 years ago
4 0

Answer:

6 right and 2 down to quadrant 4

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The first person to answer correctly will get brainliest 5 stars AND a thank you!!!!
Travka [436]

Answer:

A translation

Step-by-step explanation:

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2 years ago
If the plane moved 253km south west and ther wind blows from 60south West calculator ther age​
fomenos

Answer:

20

Step-by-step explanation:

7 0
3 years ago
Identify the expression and the value equivalent to 4 times 3 cubed
MrRa [10]

Answer:

4 \times 3^{3}\\\\4\times3 \times3\times3\\\\108

Step-by-step explanation:

Four times three cubed

Given the statement, times means multiplication.

four times three

4        x         3

It says three cubed, where cubed means raised to 3. So that means we right an exponent, and the exponent is 3.

4 x 3³

When we have an exponent, that tells you how many times you will multiply it by itself. So since the exponent is 3, we multiply 3 by itself 3 times.

3³ = 3 x 3 x 3

So 4 x 3³ = 4 x 3 x 3 x 3

Lastly, if we get the product your result will be 108.

4 x 3 x 3 x 3

=4 x 27

= 108

8 0
2 years ago
Read 2 more answers
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yulyashka [42]
B. 12 is the answer to your queation
7 0
3 years ago
The cosine equation for a function that has a period of 4 straight pi and an amplitude of 8
lara [203]

Answer:

y=4sin[2(x−π2)]−6

Step-by-step explanation:

The standard form of a sine function is

y=asin[b(x−h)]+k

where

•a : is the amplitude,

•2π/b : is the period,

•h : is the phase shift, and

•k : is the vertical displacement.

We start with classic

y=sinx :

graph{(y-sin(x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

(The circle at (0,0) is for a point of reference.)

The amplitude of this function is

a=1 .To make the amplitude 4, we need

a to be 4 times as large, so we set

a=4

.

Our function is now

y=4sinx ,and looks like:

graph{(y-4sin(x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

The period of this function—the distance between repetitions—right now is

2π , with b=1

.To make the period π , we need to make the repetitions twice as frequent, so we need

b=normal period/desired period

=2π/π=2

.

Our function is now

y=4sin(2x), and looks like: graph

{(y-4sin(2x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

This function currently has no phase shift, since

h=0

. To induce a phace shift, we need to offset

xby the desired amount, which in this case is

π2 to the right. A phase shift right means a positive

h, so we set

h = π2

.

Our function is now

y=4sin[2(x−π2)] , and looks like:graph

{(y-4sin(2(x-pi/2)))((x-pi/2)^2+y^2-0.075)=0 [-15, 15, -11, 5]}

Finally, the function currently has no vertical displacement, since

k=0

.To displace the graph 6 units down, we set

k=−6

.

Our function is now

y=4sin[2(x−π2)]−6, and looks like:graph {(y-4sin(2(x-pi/2))+6)((x-pi/2)^2+(y+6)^2-0.075)=0 [-15, 15, -11, 5]}

6 0
3 years ago
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