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Oksi-84 [34.3K]
4 years ago
7

A student had taken 7 tests and received scores of 88, 73, 81, 83, 79, 73, and 97.

Mathematics
1 answer:
bixtya [17]4 years ago
5 0

Answer:

Average is 82

Step-by-step explanation:

88 + 73 + 81 + 83 + 79 + 73 + 97 = 574

Count of numbers = 7

574/7 = 82

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Max worked 13 hours last week at the grocery store and earned $94.25.If he only worked 5 hours this week, how much money did he
Marrrta [24]
ANSWER: $36.25

Explanation: First find the rate. Divide $94.25 by 13 (hours) to get the rate. Now you know that Max earns $7.25 each hour he works. Multiply his hourly rate by 5 (hours) to get how much Max earns in five hours.
6 0
4 years ago
the Marked price of an article is rupees 1600 if it is sold for rupees 1420 what is the discount rate​
Naya [18.7K]

Answer:

1600-1420= 180

Step-by-step explanation:

Given that

The Marked price of an article is rupees 1600 if it is sold for rupees 1420 then what is the discount rate

1600-1420

=180

then 180 percent is discount

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3 0
3 years ago
Read 2 more answers
In a bolt factory, machines 1,2, and 3 respectively produce 20%, 30% and 50% of the total output. of their respective outputs 5%
lorasvet [3.4K]

Answer:

a. 1/10 or 10%

b. 1/2 or 50%

Step-by-step explanation:

Since the combination of machines 1, 2 and 3 produce 100% of the total output when added together, then the probability of choosing a bolt at random that is defective is: 5 + 2 + 3 = 10% out of 100% or 10/100, which is 1/10 or 10%.

If the bolt that is choosen at random is defective, than the probability that it came from machine 1 is 5/10 or 1/2 which is also 50%.

3 0
4 years ago
Write these fractions in least common denominator2/5x+15y 1/2x+6y
Over [174]
Look at deonomators

assuming that the deonomenators are 5x+15y and 2x+6y

find their LCM
factor

5x+15y=5(x+3y)

2x+6y=2(x+3y)

LCM=10(x+3y)=10x+30y

multiply 2/(5x+15y) by 2/2=4/(10x+30y)
multiply 1/(2x+6y) by 5/5=5/(10x+30y)

if we add them
9/(10x+30y)
3 0
3 years ago
The population p (in millions) of Italy from 1990 through 2008 can be approximated by the model p=56.8e^o.oo15t , where t repres
dimulka [17.4K]

As we already have the model that describes the change of the population in Italy in terms of the years that have elapsed, we only have to replace the conditions that are requested in that equation.

Therefore to find the population of Italy in the year 2000 (t = 10 years)  substitute t = 10 in the equation and have:

p = 56.8e^{0.0015*10}\\

p=57.6584 million people

To find the population of Italy in 2008 (t = 18 years)

substitute t = 18 in the equation and have:

p=56.8e ^{0.0015*18}\\

p=58.3545 million people


To predict the population in Italy for 2015 and 2020 with this model, we substitute in the equation t = 25 and t = 30

t = 25

p=56.8e^{0.0015*25}

p=58.9704 million people


 t = 30

p=56.8e^{0.0015*30}

p=59.4144 million people

8 0
3 years ago
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