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Oksi-84 [34.3K]
3 years ago
7

A student had taken 7 tests and received scores of 88, 73, 81, 83, 79, 73, and 97.

Mathematics
1 answer:
bixtya [17]3 years ago
5 0

Answer:

Average is 82

Step-by-step explanation:

88 + 73 + 81 + 83 + 79 + 73 + 97 = 574

Count of numbers = 7

574/7 = 82

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Solve the inequality.
Vika [28.1K]

Answer:

Option C is correct

Step-by-step explanation:

      5c – 20 ≤ 15c + 10

<=> 5c - 15c ≤ 20 + 10

<=>-10c ≤ 30

<=> c ≥ -3

Hope this helps!

6 0
3 years ago
Read 2 more answers
Answer the questions by drawing on the coordinate plane below.
solniwko [45]

Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).

a) Let us discuss the rule for rotation of 90° clockwise about the origin.

If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).

x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P'(-1,-1)

Q(3,-2) --> Q'( -2,-3)

R(3,-4) --> R'(-4,-3)

b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P"(1,1)

Q(3,-2) --> Q"( 3,2)

R(3,-4) --> R"(3,4)



6 0
3 years ago
Find the peremiter of triangle ABC
cricket20 [7]

Answer:

18

Step-by-step explanation:

if AB : BC : AC is 3 : 4 : 2 and BC = 8 then AB = 6 and AC = 4

To calculate the perimeter of the triangle we add all side lengths up

4 + 6 + 8 = 18

5 0
2 years ago
Read 2 more answers
How do i find joint relative frequency?
Svet_ta [14]
A joint relative frequency is found by dividing a frequency that is not in the Total row or the Total column by the frequency’s row total or column total.
3 0
3 years ago
10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135
Viefleur [7K]
The simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.

First we must simplify the expression:
\frac{3 \sqrt{160} }{\sqrt{1350x} } =  \frac{12 \sqrt{10} }{15 \sqrt{6x} } =  \frac{4 \sqrt{10} }{5 \sqrt{6x} }

Then we factor the rational parts and cancel it out:
\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }

Then we rationalize the expression:
\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}

<span>Finally, the simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.</span>
7 0
3 years ago
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