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pentagon [3]
2 years ago
7

A line has a slope of 0 and passes through the point (9,9) what is its equation in slope-intercept form?

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
4 0

Step-by-step explanation:

The equation of the line with a slope of 0 is y=c, where c is a constant.

As the line passesvthrough a pt with a y coordinate of 9, the equation is y=9.

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7x + y = 13<br> 4x – 4y = -20
aalyn [17]

Answer: (x,y) = (1,6)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Michelle is making a scale model of her favorite car. The actual car is 8 feet long and 4 feet wide. Michelle wants her model to
AfilCa [17]

Answer:

6 inches

Step-by-step explanation:

It is given that :

Length of the actual car = 8 feet

Width of the actual car is = 4 feet

Michelle is making a model of her car.

The length of her model car  = 12 inches

Therefore, the ration is 3 : 2

So the width of the model car = 4 x 3/2

                                                 = 6 inches

7 0
2 years ago
Solve 3x-2y=15 for y?
Nikitich [7]

Answer:

y=3x-15

Step-by-step explanation:

3x-2y=15

   +2y +2y

3x=15+2y

-15 -15

y=3x-15

7 0
3 years ago
How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
\sum_{r=1}^n{1}=n
\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}
=40\frac{n(n+1)}{2}-21n^2+8n
=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0  therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

(c) the maximum value of f(x) is f(14)=196
4 0
2 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
11 months ago
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