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3 years ago

FREE 100 POINTS!!! GIVING AWAY BRAINLIEST AS WELL!!!

Mathematics

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SIZIF [17.4K]3 years ago

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Answer:

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mamaluj [8]3 years ago

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Thanks For This It Is Truly Appreciated

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If the Math Olympiad Club consists of 19 students, how many different teams of 5

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3 teams of 5 can be formed

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The goal of the fundraiser to make than $150

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Making more than $150

Let the amount to be made be x.

Then: x+$150 will be the amount needed to be made

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3 years ago

If the Nutrition Facts panel on a food label indicates that a food has 24 g of total carbohydrates, 2 g of fiber and 12 g of sug

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Answer:

Option a is correct.

Step-by-step explanation:

Since both fiber and sugar are types of carbohydrates and it is given that a portion of food has 24 gm of total carbohydrate and within which 2 gm of fiber and 12 gm of sugar.

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4 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

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3 years ago

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Answer12/0.5

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