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iogann1982 [59]
2 years ago
15

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
2 answers:
Korvikt [17]2 years ago
7 0

Answer:

A or 2

Step-by-step explanation:

natka813 [3]2 years ago
4 0
<h3>Answer:   2</h3>

Reason:

The 5's cancel out leaving the 2 behind as the final answer.

Another way to look at it is that the 5*2 up top multiplies to 10, then we divide that by the 5 in the denominator to end up with 10/5 = 2

If you are a visual learner, then draw a circle and divide it into 5 equal slices. Do this a total of five times. Each pizza having 2 slices, and 5 pizzas total, gives 2*5 = 10 slices overall. These ten slices can be rearranged into making 2 full pizzas.

See below.

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How do I solve system of equations by subsitution<br><br>​
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You need to solve for x or y in one equation and and substitute it into the other equation in place of the variable that corresponds to it.

6 0
3 years ago
Bro it easy just look
gayaneshka [121]

Answer:

then answer it

Step-by-step explanation:

4 0
3 years ago
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The cabin is worth $730,000. John paid $468,475.00, Sissy paid $251,525.12.
charle [14.2K]
John owns 64.17 percent (rounded to 64%). Sissy owns 34.45 percent (rounded to 34% or 34.5%).
6 0
3 years ago
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7. By using binomial expansion show that the value of (1.01)^12 exceed the value of (1.02)^6 by 0.0007 correct to four decimal p
BlackZzzverrR [31]

Binomial expansion is used to factor expressions that can be expressed as the power of the sum of two numbers.

The proof that (1.01)^12 exceeds (1.02)^6 by 0.0007 is\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }

The expressions are given as:

\mathbf{(1.01)^{12}\ and\ (1.02)^6}

A binomial expression is represented as:

\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}

Express 1.01 as 1 + 0.01

So, we have:

\mathbf{(1.01)^{12} = (1 + 0.01)^{12}}

Apply the above formula

\mathbf{(1.01)^{12} = ^{12}C_0 \times 1^{12 - 0} \times 0.01^0 + .........  .......... +  ^{12}C_{12} \times 1^{12 - 12} \times 0.01^{12} }}

\mathbf{(1.01)^{12} = 1 \times 1 \times 1 + .........  .......... +  1 \times 1 \times 10^{-24} }}

\mathbf{(1.01)^{12} = 1  + .........  .......... +  10^{-24} }}

This gives

\mathbf{(1.01)^{12} = 1.1268\ (approximated)}

Similarly,

Express 1.02 as 1 + 0.02

So, we have:

\mathbf{(1.02)^6 = (1 + 0.02)^6}

Apply \mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}

\mathbf{(1.02)^6 = ^6C_0 \times 1^{6 - 0} \times 0.02^0 +  ^6C_1 \times 1^{6 - 1} \times 0.02^1 +.............. + ^6C_6 \times 1^{6 - 6} \times 0.02^6 }\mathbf{(1.02)^6 = 1 \times 1 \times 1 +  6 \times 1 \times 0.02 +.............. + 1 \times 1 \times 6.4 \times 10^{-11} }

\mathbf{(1.02)^6 = 1 +  0.12 +.............. + 6.4 \times 10^{-11} }

This gives

\mathbf{(1.02)^6 = 1.1261\ (approximated) }

Calculate the difference as follows:

\mathbf{(1.01)^{12} - (1.02)^6 \approx 1.1268 - 1.1261 }

\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }

The above equation means that:

(1.01)^12 exceed the value of (1.02)^6 by 0.0007

Read more about binomial expansions at:

brainly.com/question/9554282

7 0
3 years ago
Jonathon is using a six-sided die to conduct an experiment. What would be the probability that the die would land on the number
crimeas [40]
The probability of landing on a 4 when throwing a die is 1/6.
to find the probability of rolling the same number you have to times this

1/6*1/6*1/6=1/216

hope this helped!
5 0
3 years ago
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