In how many ways can a

Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "r" from a collection or a group of distinct objects which we can name "n". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

$C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}$

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = $(\frac{14}{3})$ = $\frac{14!}{(3!(14-3)!)}$

= $\frac{87178291200}{(6 X 39916800)}$

= $\frac{87178291200}{239500800}$

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

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sin(θ) = ± √(1 - cos²(θ))

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We're given that θ belongs to the third quadrant, for which both sin(θ) and cos(θ) are negative. So if cos(θ) = -4/5, we get

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