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nadezda [96]
3 years ago
10

In how many ways can a

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

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Answer:

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Step-by-step explanation:

1.5 > 2 1/2 False

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1.5 > 2 1/2

1/2 = 0.5

2 + 0.5 = 2.5

1.5 is not > 2.5

1.5 < 2.5

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0.5 = 0.5

-2.5 > -1.5

Negative numbers are oposite of positive numbers when using inequalities. Just as 0 < 1, -1 < 0.

-2.5 is not > -1.5

-2.5 < -1.5

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7 0
3 years ago
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Answer:

IV

In the fourth quadrant (IV).

Step-by-step explanation:

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Solve for x squared equals seventeen please <br>x^2 = 17​
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What is x when the equation is 5|2x+3|=45?
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The Rivertown city council is attempting to choose one of four sites (A, B, C, or D) as the location for its new emergency facil
Vikki [24]

Answer:

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Step-by-step explanation:

Given :

proposed-site Area-Served

1 2 3 4

A 5.2 4.4 3.6 6.5

B 6.0 7.4 3.4 4.0

C 5.8 5.9 5.9 5.8

D 4.3 4.8 6.5 5.1

Area 1 2 3 4

Number-runs 150 65 175 92

Computing the weighted average for the 4 sites :

Site A:

((150*5.2) + (65*4.4) + (175*3.6) + (92*6.5)) / (150 + 65 + 175 + 92)

= 2294 / 482

= 4.7593

Site B:

((150*6.0) + (65*7.4) + (175*3.4) + (92*4.0)) / (150 + 65 + 175 + 92)

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= 4.863

Site C:

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= 2819.6/ 482

= 5.850

Site D:

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= 2563.7/ 482

= 5.319

From the weighted average response time computed for the different sites ;

The best location for the emergency facility would be one with the least average response time; which is SITE A.

7 0
3 years ago
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