If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Given that the sum of an integer and 7 more than the next consecutive integer is 66.
Integer is a number that is written without a fraction component. It can be positive as well as negative.
let the first integer be x.
Consecutive integer will be x+1.
Sum of integer and 7 more than the next consecutive integer is 66.
Sum according to the given information=x+x+1+7
=2x+8
2x+8=66
2x=66-8
2x=58
x=58/2
x=29
Next integer=29+1-30.
Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Learn more about integers at brainly.com/question/17695139
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14x - (2x - y) - y
14x + (-1(2x - y)) - y
14x + (-1(2x) - 1(-y)) - y
14x + (-2x + y) - y
14x + 1(-2x + y) - y
14x + 1(-2x) + 1(y) - y
14x - 2x + y - y
14x - 2x
12x
Answer:
2.96
Explanation:
37/x=100/8
(37/x)*x=(100/8)*x - we multiply both sides of the equation by x
37=12.5*x - we divide both sides of the equation by (12.5) to get x
37/12.5=x
2.96=x
x=2.96
Since x represents the year, year 15 will be 15 years.
Plug in "15" as your "x"
y = -2(15)^2 + 36(15) + 6
15^2 = 225 (Exponents come before multiplication)
y = -2(225) + 36(15) + 6
y = -450 + 540 + 6
y = 90 + 6
y = 96
<em>The answer is B</em>
