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2 years ago

What is the equation of the line that is parallel to the given

Mathematics

1 answer:

Mrac [35]2 years ago

8 0

Answer:

Step-by-step explanation:

is the given line 3x - 4y = -17?

then,

- 4y = -3x -17

y=(3/4)x+17/4

it is parallel, so slope of our line is 3/4 or 0.75

y=0.75x+b

next, lets plug in the given point to get the y-int

2=0.75*(-3)+b

2=-2.25+b

b-2.25=2

b=4.25

the equation is y=0.75x+4.25

does this clear anything, or am I off topic? please tell me I will help you

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Sam can mow 2 lawns in 3/4 hour.

MrRa [10]

Answer:

5 lawns is the answer don't forget to mark as brainliest!

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2 years ago

1. Find the Product of 8.02 and 6.1 and correct your answer to the highest whole number. 2. How many pieces of ribbon each 6cm l

Alja [10]

Answer:

1. 14

2.400 pieces

Step-by-step explanation:

1. 8.02+6.1= 14.12, since its less than 14.5 you must round down to 14

2. remember 1 meter is 100 centimeters, thus to find how many centimeters are in 24 m multiply 100 by 24. this will get 2400 centimeters

divide 2400/6 and you will get 400

5 0

2 years ago

Read 2 more answers

Assume ABC Company deposits $90,000 with First National Bank in an account earning interest at 6% per annum, compounded semi-ann

maw [93]

Answer:

Step-by-step explanation:

I'm goig to assume that the formula we need here is the following:

$A(t)=P(1+\frac{r}{n})^{(n)(t)$

where A(t) is the amount in the account after the compounding is done, n is the number of times per year the compounding occurs, r is the rate in decimal form, and t is the time in years. Filling in accordingly,

$A(t)=90000(1+\frac{.06}{2})^{(2)(5)}$ and simplifying a bit,

$A(t)=90000(1.03)^{10}$ and simplifying a bit more,

A(t) = 90000(1.343916379) so

the amount in the account after 5 years is

A(t) = 120,952.47

5 0

2 years ago

What is the derivative of the following function? f(x) = 4x^6/cos^5(x)

KIM [24]

Answer:

$f'(x) = \frac{24x^{5} \cos x + 20x^{6}\sin x}{\cos^{6}x }$

Step-by-step explanation:

We have to find the derivative of the following function:

$f(x) = \frac{4x^{6} }{\cos^{5} x }$

Now, differentiating both sides with respect to x we get,

$f'(x) = \frac{\cos^{5}x (24x^{5}) - 4x^{6}(5\cos^{4}x )(- \sin x)}{(\cos^{5}x )^{2}}$

⇒ $f'(x) = \frac{ 24x^{5} \cos x + 20 x^{6}\sin x}{\cos^{6}x }$ (Answer)

{Since, we know that, $\frac{d(mx^{n} )}{dx} = m \times n x^{(n - 1)}$ and $\frac{d(\cos^{n} x)}{dx} = n \cos^{(n - 1)} x(- \sin x)$ }

5 0

3 years ago

Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic f

diamong [38]

Answer:

314 ft²

Step-by-step explanation:

Data provided in the question:

Depth (height) of the pool = $\frac{1}{2}$ of its radius

let the radius be 'r' ft

thus,

Depth (height) of the pool, h = $\frac{r}{2}$ ft

Volume of the pool = 1570 ft³

also,

Volume of cylinder = πr²h

thus,

1570 ft³ = πr²h

1570 ft³ = $\pi r^2(\frac{r}{2})$

3140 = 3.14 × r³ [ π = 3.14 ]

r³ = 1000 ft³

r = 10 ft

Thus,

Area of the bottom surface = πr²

= 3.14 × 10²

= 314 ft²

5 0

2 years ago