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3 years ago

11

The stage manager of a school play creates a rectangular acting area of 42 square yards. String lights will outline the acting a

rea. To the nearest whole number, how many yards of string lights does the manager need to enclose this area?

1 answer:

Sliva [168]3 years ago

5 0

6+6+7+7
12+14
26

So 26 is the answer

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Elodia [21]

Answer:

33 degrees

Step-by-step explanation:

(4x+1) and (2x-19) add up to 180 degrees

$(4x+1)+(2x-19)=180\\6x-18=180\\6x=198\\x=33$

3 0

2 years ago

13<img src="https://tex.z-dn.net/?f=13%5Cfrac%7B1%7D%7B4%7D%20%2B2n%3D27%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1" title="13\frac{1

Len [333]

Answer:

7 1/8

Step-by-step explanation:

Assuming that the first 13 was a mistake then the equation would be 13 1/2 + 2n = 27 3/4

subtrace 13 1/2 from 27 3/4

14 1/4

divide by 2

7 1/8

7 0

3 years ago

In a parallel circuit, ET = 208 V, R = 33 kΩ, and XL = 82 kΩ. What is the apparent power?

jeka94

Answer:

Apparent power is 1.413Volt-Amps.

Step-by-step explanation:

We are given that in a parallel circuit, $E_{T}=208V$ ,R=33kΩ and $X_{L}$ =82kΩ.

And we are asked to find apparent power.

Apparent power is the combination of true power and reactive power.

In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.

Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.

True power= $\frac{E_{T}^{2}}{R}=\frac{208^{2}}{33000}=1.311watts$

Reactive power= $\frac{E_{T}^{2}}{X_{L}}=\frac{208^{2}}{82000}=0.528VARs$

Hence apparent power= $\sqrt{1.311^{2}+0.528^{2}} =1.413VA$

5 0

4 years ago

Solve. −4 3/4=x−1 1/5 What is the solution to the equation? Enter your answer as a simplified mixed number in the box.

cluponka [151]

Answer: x= -3 11/20 Decimal form: x=-3.55

Step-by-step explanation:

7 0

2 years ago

Help me with this plz guys ur my only hope

Gnesinka [82]

<h2><u>Answer:</u></h2>

Pi = 3.14

Diameter (d) = 86 cm

•°• Radius (r) = 86 ÷ 2 = 43 cm (radius is 1/2 of diameter)

Area of the circle = ?

Formula,

$\pi( {r})^{2}$

Substitute the value of 'r' & pi in the formula.

$\pi(43) {}^{2} \\ = 3.14 \times 43 {}^{2} \\ = 3.14 \times 1849 \\ = 5805.86 \: \: cm {}^{2}$

⎆ The area of the circle is about <u>5</u><u>8</u><u>0</u><u>5</u><u>.</u><u>8</u><u>6</u><u> </u>cm² (approx.)

5 0

3 years ago