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Zanzabum
2 years ago
9

Maybell just purchased $2075 worth of jewelry. If she marks up her cost by 30% and sells all of the jewelry, what will be the to

tal retail cost of all the jewelry?
Mathematics
2 answers:
nika2105 [10]2 years ago
7 0

Answer:

A

Step-by-step explanation:

I did it before

Whitepunk [10]2 years ago
4 0

Answer:

times 2075 by .30 and that's your answer

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Find the number of permutations of the first 9 letters of the alphabet, taking 4 letters at a time.
Vinil7 [7]

Solution-

First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I

Total number of ways of selection of 4 letters from 9 alphabets = 9C4

=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126

The number of ways of arranging these 4 numbers = 4! = 24

∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024

∴ option number 2 is correct.

8 0
3 years ago
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Alex_Xolod [135]
Its the third option y-9=-1/4(x+2) because the equation for point slope form is y-y1= m(x-x1) so because there is a negative 2 it is a positive 2. Remember a negative minus a negative is a positive. Hope this helped :)!
7 0
2 years ago
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3/12 1/6 and 1/3 same denominator
iogann1982 [59]
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5 0
3 years ago
Which is an asymptote of the graph of the function y = cot ( x - 2pi / 3 )
vesna_86 [32]
\bf y=cot\left(x-\frac{2\pi }{3}  \right)\implies y=\cfrac{cos\left(x-\frac{2\pi }{3}  \right)}{sin\left(x-\frac{2\pi }{3}  \right)}

now, if the denominator turns to 0, the fraction becomes undefined, and you get a "vertical asymptote" when that happens, so let's check when is that

\bf sin\left(x-\frac{2\pi }{3}  \right)=0\implies sin^{-1}\left[ sin\left(x-\frac{2\pi }{3}  \right) \right]=sin^{-1}(0)
\\\\\\
x-\frac{2\pi }{3}=
\begin{cases}
0\\
\pi 
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{2\pi }{3}\\
\frac{5\pi }{3}
\end{cases}

now, at those angles, the function is asymptotic, check the picture below

3 0
3 years ago
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Find the product of (3^6)(3)(3^5) Express your answer using exponents
VikaD [51]

Answer:

3^12

Step-by-step explanation:

When multiplying the same number with different exponents you have to add the the exponents. For example:

a^x + a^y = a ^{x+y}

So (3^6)(3)(3^5) or (3^6)(3^1)(3^5) = 3^(6+1+5) = 3^12

6 0
3 years ago
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