All categories

3 years ago

Jalen says that the height, radius, and diameter of a cone lie entirely on the base of the cone. What is Jalen’s error?

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

7 0

The Diameter wouldn’t lie on the base but the height and the radius is half of the base

Oxana [17]3 years ago

4 0

Answer:

The height does not lie on the base because it is perpendicular to the base.

Step-by-step explanation:

You might be interested in

Please Help! Given triangles ABC and DEF, which statement explains a way to determine if the two figures are similar?

forsale [732]

Answer:

Step-by-step explanation:

i took the test

5 0

3 years ago

Read 2 more answers

Plssssss answerrrrrrr

densk [106]

Don’t take my word for it but I think 3rd option

8 0

3 years ago

A car moved at a speed of 90km/hr for 3 minutes.What distance did it cover?

aniked [119]

Answer:

270kilometers

Step-by-step explanation:

To find the distance, all you have to do is the speed · time

In these types of distance time and word problems, you multiply the other factors, 90 and 3, The time(T) · The speed(S)

So. 90(S) · 3(T) = 270(D)

5 0

3 years ago

What is the solution to -55+q=7 A. a=-62 B. q=62 C. q=42 D. q=-42

Scorpion4ik [409]

Answer:

C, as q = 62.

Step-by-step explanation:

When you have an equation, your goal is to get the letter you are solving for alone. To do this, you employ a simple rule: what you do to one side of the equals sign, you must do the other.

To isolate q in -55 + q = 7, you must add 55 to the left side. q is now alone. However, because we added 55 to the left side, we must also do it to the right! 7 + 55 = 62, so the new right side is 62. Hence, we get to this:

q = 62

The answer is now in plain sight!

4 0

3 years ago

Read 2 more answers

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$