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kifflom [539]
3 years ago
9

Karan needs to choose between two gym plans. He can either pay a $150 joining fee and a $10 monthly fee, or he can pay a $50 joi

ning fee and a $30 monthly fee.
On what month will the cumulative costs of the plans be equal, and what will those total costs be

Answer: Karan will pay a cumulative cost of___?___ dollars with either plan to go to the gym for __?__ months.
Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0

Let  x be the month on which the fee for two plans are equal.

Therefore,

150 + 10x = 50 + 30x

10x - 30x = 50 - 150

-20x = -100

x = 5

Cumulative cost = 150 + 10(5)

                           = 150 + 50

                           = 200

Hence, Karan will pay a cumulative cost of $200 dollars with either plan to go to the gym for 5 months.

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Forty-two people charter a bus for $788. Estimate the amount each person pays.<br> Your answer
max2010maxim [7]

Answer:

$20

Step-by-step explanation:

If 42 people equally share the bus price off 788 dollars then ech person would be expected to pay 788/42 = $18.76 (2dp) though I suppose if you needed to estimate it, you would round 788 to 800 and 42 down to 40 which would give you 800/40 = 20 dollars per person which is a pretty close estimate.

Hope this helped!

6 0
3 years ago
Show that the series is convergent by the alternating series test, and find the number of terms necessary to estimate the sum of
Murljashka [212]

Answer:

6 terms

Step-by-step explanation:

2 − 2/4 + 2/9 − 2/16 + ...

∑ (-1)ⁿ⁺¹ 2 / n²

Applying alternating series test:

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2/(n+1)² < 2/n², so the series is decreasing.

Therefore, the series converges.

2/(n+1)² < 0.05

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(n+1)² > 40

n+1 > 6.32

n > 5.32

n = 6

7 0
3 years ago
You eat 18 grams of your daily carbohydrates which is 6% of daily needs what is your daily need
adell [148]

Answer:

300 grams

Step-by-step explanation:

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7 0
3 years ago
Which factor does the width of the peak of a normal curve depend on?
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3 years ago
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4/5 as a whole number plz :)
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The answer is 1 because4 is close to 5
8 0
3 years ago
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