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denis-greek [22]
3 years ago
15

Select the best answer for the question

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

the answer is20 inches

Step-by-step explanation:

a square has 4 sides so you divide the total of 80 by 4.

80÷4=20

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​Recently, a random sample of 13-18 year olds was​ asked, "How much do you currently have in​ savings?" The data in the table re
Sonbull [250]

Answer:

μ = 235.38

σ = 234.54

Step-by-step explanation:

Assuming the table is as follows:

\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]

This is an example of grouped data, where a range of values is given rather than a single data point.  First, find the total frequency.

n = 339 + 86 + 55 + 18 + 11 + 8 + 3

n = 520

The mean is the expected value using the midpoints of each range.

μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

μ = 122400 / 520

μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

σ² = 55009.7

The standard deviation is:

σ = 234.54

6 0
3 years ago
Please help! Brainlyest answer!
Fudgin [204]

Answer:

113 feet

Step-by-step explanation:

6 0
3 years ago
Cameron sells tickets at a movie theater on Friday night she work from 4 p.m. to 10 p.m. and sold out about 25 tickets every hou
postnew [5]

4 pm to 10 pm = 6 hours

25 x 6 = 150 tickets

3 0
4 years ago
Can someone help me solve this differentiation/tangent problem?
nirvana33 [79]
A)

\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot  f'(x)}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\
-------------------------------\\\\
g(5)=(5)^2f(5)\implies g(5)=125
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}
\begin{cases}
x=5\\
y=125\\
\stackrel{m}{g'(5)}=550
\end{cases}\implies y-125=550(x-5)
\\\\\\
y-125=550x-2750\implies y=550x+400



b)

\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}
\\\\\\
h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\
-------------------------------\\\\

\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad 
\begin{cases}
x=5\\
y=-5\\
\stackrel{m}{-10}
\end{cases}\implies y-(-5)=-10(x-5)
\\\\\\
y+5=-10x+50\implies y=-10x+45
3 0
4 years ago
it cost $6 to join an online DVD club and $2.50 to rent each DVD. write an equation for the relationship that shows the total co
bonufazy [111]
6+2.50=y
y=8.5

Hope this helped☺☺
6 0
3 years ago
Read 2 more answers
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