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2 years ago

Select the best answer for the question

Mathematics

1 answer:

Ksivusya [100]2 years ago

6 0

Answer:

the answer is20 inches

Step-by-step explanation:

a square has 4 sides so you divide the total of 80 by 4.

80÷4=20

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the slope of the line below is 2. use the labeled point to find a point-slope equation of the line. (1, 9)

hram777 [196]

Answer:

Step-by-step explanation:

y - 9 = 2(x - 1)

y - 9 = 2x - 2

y = 2x + 7

8 0

2 years ago

A bag contains red, green, and yellow marbles. The probability of selecting a red marble is 35%. What is the probability of not

KonstantinChe [14]

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

6 0

1 year ago

Please help its from the lines and angles chapter

Murrr4er [49]

This is the answer of this question

4 0

2 years ago

A provider order has been received for a dobutamine (dobutrex®) drip at 7 mcg/kg/min. the patient's weight is 220 lbs. how many

Liula [17]

To figure this out you first need to determine how many kg there are in 220 lbs. 1 lb equals 0.454 kg, so 220 lbs= 99.88 kg.

It states that a patient receives 7mcg per kg per minute, so the patient will receive 7 x 99.88=699.16 mcg per minute.

You need to convert this to a number of mcg per hour, so multiply the amount by 60 to get 41949.6 mcg per hour.

4 0

2 years ago

According to the Department of Transportation, 27% of domestic flights were delayed in the last year at JFK airport. Five flight

Mars2501 [29]

Answer:

The probability that all the five flights are delayed is 0.2073.

Step-by-step explanation:

Let X = number of domestic flights delayed at JFK airport.

The probability of a domestic flight being delayed at the JFK airport is, P (X) = p = 0.27.

A random sample of n = 5 flights are selected at JFK airport.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={5\choose x}0.27^{x}(1-0.27)^{5-x};\ x=0,1,2...$

Compute the probability that all the five flights are delayed as follows:

$P(X=5)={5\choose 5}0.27^{5}(1-0.27)^{5-5}=1\times 1\times 0.207307=0.2073$

Thus, the probability that all the five flights are delayed is 0.2073.

4 0

2 years ago